Abrams is a town in Oconto County, Wisconsin, United States. The population was 1,757 at the 2000 Census.
Geography
According to the United States Census Bureau, the town has a total area of 37.6 square miles (97.3 km²), of which, 37.5 square miles (97.0 km²) of it is land and 0.1 square miles (0.3 km²) of it (0.29%) is water.
Demographics
As of the census[2] of 2000, there were 1,757 people, 652 households, and 494 families residing in the town. The population density was 46.9 people per square mile (18.1/km²). There were 700 housing units at an average density of 18.7/sq mi (7.2/km²). The racial makeup of the town was 98.52% White, 0.80% Native American, 0.06% Asian, and 0.63% from two or more races. Hispanic or Latino of any race were 0.28% of the population.
There were 652 households out of which 35.1% had children under the age of 18 living with them, 66.1% were married couples living together, 6.6% had a female householder with no husband present, and 24.1% were non-families. 19.2% of all households were made up of individuals and 6.6% had someone living alone who was 65 years of age or older. The average household size was 2.69 and the average family size was 3.06.
In the town the population was spread out with 26.5% under the age of 18, 6.9% from 18 to 24, 33.2% from 25 to 44, 24.8% from 45 to 64, and 8.5% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 108.7 males. For every 100 females age 18 and over, there were 105.2 males.
The median income for a household in the town was $51,250, and the median income for a family was $53,510. Males had a median income of $37,261 versus $23,542 for females. The per capita income for the town was $20,889. About 1.7% of families and 4.9% of the population were below the poverty line, including 6.3% of those under age 18 and 6.4% of those age 65 or over.
Notable natives
References
Coordinates: 44°46′45″N 88°03′35″W / 44.77917°N 88.05972°W / 44.77917; -88.05972
