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In Galaxies

Arcturus has a radius about 26 times that of our Sun. Our Sun has a radius about 109 times that of Earth. So a quick bit of math: 109 x 26 = 2,834 times th…at of Earth (MORE)

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In Uncategorized

The schwarzschild radius of the Earth is about 8.7 x 10 to the negative 3m. The schwarzschild radius is the radis of a sphere that is around a non-rotating blackhole. You fin…d the Rs, or radis, by multiplying the gravitational constant(G), the mass(M), and two. You divide this by the speed of light(c) squared. (MORE)

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There are many ways this can be done. The ancient Greeks measured the lengths of shadows at two different locations a few hundred miles apart on a roughly north…-south baseline at noon on the same day of the year. From this using trigonometry the circumference was computed, then using the relationship of circumference to radius the radius can be computed. Almost surprisingly the figure they got was very close to the modern figure. Columbus repeated this calculation, but due to a combination of bad data in the sources he used (he did not make the measurements himself) and calculation errors on his part he got a result roughly 2/3 of the correct value (an error equivalent to elimination of the pacific ocean and the Americas); which convinced him he could easily sail to China & India. An equivalent calculation can be done using measurements of star positions at night from different locations, using any baseline (e.g. north-south, east-west, diagonals) between the locations as long as the time and day are identical when the measurements are made. (MORE)

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In Geometry

There is no exact radius of the Earth, but the average is 3,959 miles or 20,903,520 feet. The Earth is rotating on it's axis and because of this rapid rotation the Earth's po…les tend to flatten. Which makes the radius from the center to the equator larger than from the center to the poles. (MORE)

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In Physics

Yes, in a way. If the radius of the Earth decreased but it's mass stayed the same, then the forces "pulling" on you (weight) would increase and you would be heavier. If th…e radius of the Earth increased and the mass stayed the same, then you would be lighter. You would actually weigh less on the top of Mount Everest than on the beach of Honolulu. BTW: This is not a good idea for a weight loss program. (MORE)

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In Physics

Earth's Circumference at the Equator: 24,901.55 miles (40,075.16 km) Earth's Circumference Between the North and South Poles: 24,859.82 miles (40,008 km) Earth's Diamete…r at the Equator: 7,926.28 miles (12,756.1 km) Earth's Diameter at the Poles: 7,899.80 miles (12,713.5 km) Average Distance from the Earth to the Sun: 93,020,000 miles (149,669,180 km) Average Distance from the Earth to the Moon: 238,857 miles (384,403.1 km) Radius of Earth = 6 378.1 kilometers or about 3961.3 miles. .
Radius of the Earth is about: 3440.07 Nautical miles(nm) The radius (the distance from the surface to the middle) of the Earth is 6, 378.1 km. About 6400 kilometers. The Earth's radius is approximately 6,376,136 metres along the equator and approximately 6,376,115 metres along the Prime Meridian. Earth has 3 different radiuses. The mean radius is 6,371 kilometers. The equatorial radius is 6,378.1 kilometers. The polar radius is 6,356.8 kilometers The radius of the earth is approximately 6378.1km (MORE)

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Light and radio signals seldom travel in straight lines through air, because the pressure, temperature, and density of air change with altitude. Light and radio signals al…most always curve vertically, and usually downward. If you were to draw a picture of the real earth's surface, with the real path of a light beam or radio signal traveling above it, the surface of the earth would curve downward on the drawing, and the light or radio signal would also curve above it. The distance between the surface and the light or radio signal would change across the drawing, depending on how strongly the signal curved, and in which direction (up or down). It would be possible to distort the drawing in such a way as to make the light or radio signal appear to be a straight line. In order to do that, you'd have to change the curvature of the earth's surface on the drawing, and maintain the original spacing between the surface and the radio signal at every point. The number by which you have to multiply the true earth radius in order to make the light or radio signal's path appear straight on the drawing, is the "effective earth radius factor". It's a characteristic of atmospheric conditions (specifically, the vertical gradient of the atmosphere's index of refraction), and it's used in designing the optimum physical configuration of point-to-point radio links, i.e. how high above the ground to mount the antennas at each end of the link. (MORE)

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In Uncategorized

the 5s because it has better service but it dosent have diffrent colrs just silver gold and black

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Since the earth isn't a perfect sphere it's hard to determine the exact diameter at both poles. But the well-respected measurement at both poles is about 7,899.80 miles, give …or take. (MORE)

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20c + 5 = 5c + 65 Divide through by 5: 4c + 1 = c + 13 Subtract c from both sides: 3c + 1 = 13 Subtract 1 from both sides: 3c = 12 Divide both sides by 3: c = 4