Share on Facebook Share on Twitter Email
Answers.com

Isochoric process

 
Wikipedia: Isochoric process
Isochoric Process in the Pressure volume diagram. In this diagram, pressure increases, but volume remains constant.

An isochoric process, also called a constant-volume process, an isovolumetric process, or an isometric process, is a thermodynamic process during which the volume of the closed system undergoing such process remains constant. In nontechnical terms, an isochoric process is exemplified by the heating or the cooling of the contents of a sealed non-deformable container: The thermodynamic process is the addition or removal of heat; the isolation of the contents of the container establishes the closed system; and the inability of the container to deform imposes the constant-volume condition.

Contents

Theory

If the volume stays constant: (ΔV = 0), this implies that the process does no pressure-volume work, since such work is defined by

ΔW = PΔV,

where P is pressure (no minus sign; this is work done by the system).

By applying the first law of thermodynamics, we can deduce that ΔU the change in the system's internal energy, is

ΔU = Q

for an isochoric process: all the heat being transferred to the system is added to the system's internal energy, U. If the quantity of gas stays constant, then this increase in energy is proportional to an increase in temperature,

Q = nCVΔT

where CV is molar specific heat for constant volume.

On a pressure volume diagram, an isochoric process appears as a straight vertical line. Its thermodynamic conjugate, an isobaric process would appear as a straight horizontal line.

Ideal Gas

If an ideal gas is used in an isochoric process, and the quantity of gas stays constant, then the increase in energy is proportional to an increase in temperature and pressure. Take for example a gas heated in a rigid container: the pressure and temperature of the gas will increase, but the volume will remain the same.

Applications

Ideal Otto Cycle

In the ideal Otto cycle we found an example of an isochoric process when we assume an instantaneous burning of the gasoline-air mixture in an internal combustion engine car. There is an increase in the temperature and the pressure of the gas inside the cylinder while the volume remains the same.

Derivation

From the First Law of Thermodynamics, for a reversible process (thermodynamics) it is known that

dU = dQdW

Replacing work (physics) with a change in volume gives

dU = dQPdV

Since the process is isochoric, dV = 0, the previous equation now gives

dU = dQ

Using the definition of specific heat capacity at constant volume

Cv = dU / dT

dQ = nCvdT

Integrating both sides yields

Q = n\int_a^b \! C \, dT.

Where C is specific heat capacity at constant volume, a is initial temperature and b is final temperature. We conclude with:

Q = n C_v \Delta T\

Etymology

The noun isochor and the adjective isochoric derive from the Greek word stems ἴσος (isos) meaning "equal", and χώρος (choros) meaning "space."

See also

References

http://lorien.ncl.ac.uk/ming/webnotes/Therm1/revers/isocho.htm


Search unanswered questions...
Enter a question here...
Search: All sources Community Q&A Reference topics
 
 

 

Copyrights:

Wikipedia. This article is licensed under the Creative Commons Attribution/Share-Alike License. It uses material from the Wikipedia article "Isochoric process" Read more