Positive-definite matrix: Information from Answers.com

In linear algebra, a positive-definite matrix is a (Hermitian) matrix which in many ways is analogous to a positive real number. The notion is closely related to a positive-definite symmetric bilinear form (or a sesquilinear form in the complex case).

1 Definition
2 Examples
3 Characterizations
- 3.1 Quadratic forms
4 Negative-definite, semidefinite and indefinite matrices
5 Further properties
6 Non-Hermitian matrices
7 See also
8 Notes
9 References

Definition

An n × n real symmetric matrix M is positive definite if z^TMz > 0 for all non-zero vectors z with real entries ( $z \in \mathbb{R}^n$ ), where z^T denotes the transpose of z.

For complex matrices, this definition becomes: a Hermitian matrix M is positive definite if z^*Mz > 0 for all non-zero complex vectors z, where z^* denotes the conjugate transpose of z. The quantity z^*Mz is always real because M is a Hermitian matrix. For this reason, positive-definite matrices are often defined to be Hermitian matrices satisfying z^*Mz > 0 for non-zero z. The section Non-Hermitian matrices discusses the consequences of dropping the requirement that M be Hermitian.

Examples

The matrix $M_0 = \begin{bmatrix} 1 & 0 \\ 0 & 1\end{bmatrix}$ is positive definite. For a vector with entries $\textbf{z}= \begin{bmatrix} z_0 \\ z_1\end{bmatrix}$ the quadratic form is $\begin{bmatrix} z_0 & z_1\end{bmatrix} \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} \begin{bmatrix} z_0 \\ z_1\end{bmatrix}=z_0^2+z_1^2;$ when the entries z₀, z₁ are real and at least one of them nonzero, this is positive.

The matrix $M_1 = \begin{bmatrix} 0 & 1 \\ 1 & 0\end{bmatrix}$ is not positive definite. When $\textbf{z}= \begin{bmatrix} 1\\ -1\end{bmatrix}$ the quadratic form at z is then

$\begin{bmatrix} 1 & -1\end{bmatrix} \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} \begin{bmatrix} 1 \\ -1\end{bmatrix}=-2 < 0.$

Another example of positive definite matrix is given by

$A = \begin{bmatrix} 2&-1&0\\-1&2&-1\\0&-1&2 \end{bmatrix}.$

It is positive definite since for any non-zero vector $x = \begin{bmatrix} x_1\\x_2\\x_3 \end{bmatrix}$ , we have

$x^{t}Ax = \begin{bmatrix} x_1&x_2&x_3 \end{bmatrix} \begin{bmatrix} 2&-1&0\\-1&2&-1\\0&-1&2 \end{bmatrix} \begin{bmatrix} x_1\\x_2\\x_3 \end{bmatrix}$

$= 2x_1^{2} - 2x_1x_2 + 2x_2^{2} - 2x_2x_3 + 2x_3^{2}$

$= x_1^{2}+(x_1 - x_2)^{2} + (x_2 - x_3)^{2}+x_3^{2}> 0.$

Characterizations

Let M be an n × n Hermitian matrix. The following properties are equivalent to M being positive definite:

1.	All eigenvalues $λ i$ of $M$ are positive. Recall that any Hermitian M, by the spectral theorem, may be regarded as a real diagonal matrix D that has been re-expressed in some new coordinate system (i.e., $M = P - 1 D P$ for some unitary matrix P whose rows are orthonormal eigenvectors of M, forming a basis). So this characterization means that M is positive definite if and only if the diagonal elements of D (the eigenvalues) are all positive. In other words, in the basis consisting of the eigenvectors of M, the action of M is component-wise multiplication with a (fixed) element in Cⁿ with positive entries.
2.	The sesquilinear form $\langle \mathbf{x},\mathbf{y}\rangle := \mathbf{y}^*\mathbf{M}\mathbf{x}$ defines an inner product on Cⁿ. (In fact, every inner product on Cⁿ arises in this fashion from a Hermitian positive definite matrix.)
3.	M is the Gram matrix of some collection of linearly independent vectors $\textbf{x}_1,\ldots,\textbf{x}_n \in \mathbb{C}^k$ for some k. That is, M satisfies: $M_{ij} = \langle \textbf{x}_i, \textbf{x}_j\rangle = \textbf{x}_i^{} \textbf{x}_j.$ The vectors x_i* may optionally be restricted to fall in Cⁿ. In other words, M is of the form AA* where A is not necessarily square but must be injective in general.
4.	All the following matrices have a positive determinant (Sylvester's criterion): the upper left 1-by-1 corner of $M$ the upper left 2-by-2 corner of $M$ the upper left 3-by-3 corner of $M$ ... $M$ itself In other words, all of the leading principal minors are positive. For positive semidefinite matrices, all principal minors have to be non-negative. The leading principal minors alone do not imply positive semidefiniteness, as can be seen from the example $\begin{bmatrix} 1 & 1 & 1 \\ 1 & 1 & 1 \\ 1 & 1 & 0 \end{bmatrix}.$
5.	There exists a unique lower triangular matrix $L$ , with strictly positive diagonal elements, that allows the factorization of $M$ into $M = L L $ . where $L $ is the conjugate transpose of $L$ . This factorization is called Cholesky decomposition.

For real symmetric matrices, these properties can be simplified by replacing $\mathbb{C}^n$ with $\mathbb{R}^n$ , and "conjugate transpose" with "transpose."

Quadratic forms

Echoing condition 2 above, one can also formulate positive-definiteness in terms of quadratic forms. Let K be the field R or C, and V be a vector space over K. A Hermitian form

$B : V \times V \rightarrow K$

is a bilinear map such that B(x, y) is always the complex conjugate of B(y, x). Such a function B is called positive definite if B(x, x) > 0 for every nonzero x in V.

Negative-definite, semidefinite and indefinite matrices

The n × n Hermitian matrix M is said to be negative-definite if

$x^{*} M x < 0\,$

for all non-zero $x \in \mathbb{C}^n$ (or, all non-zero $x \in \mathbb{R}^n$ for the real matrix).

It is called positive-semidefinite (or sometimes nonnegative-definite) if

$x^{*} M x \geq 0$

for all $x \in \mathbb{C}^n$ (or, all $x \in \mathbb{R}^n$ for the real matrix).

It is called negative-semidefinite if

$x^{*} M x \leq 0$

for all $x \in \mathbb{C}^n$ (or, all $x \in \mathbb{R}^n$ for the real matrix).

A matrix M is positive-semidefinite if and only if it arises as the Gram matrix of some set of vectors. In contrast to the positive-definite case, these vectors need not be linearly independent.

For any matrix A, the matrix A^*A is positive semidefinite, and rank(A) = rank(A^*A). Conversely, any positive semidefinite matrix M can be written as M = A^*A; this is the Cholesky decomposition.

A Hermitian matrix which is neither positive- nor negative-semidefinite is called indefinite.

A matrix is negative definite if all kth order leading principal minors are negative if k is odd and positive if k is even.

A matrix is negative-definite, negative-semidefinite, or positive-semidefinite if and only if all of its eigenvalues are negative, non-positive, or non-negative, respectively.

Further properties

If $M$ is positive-semidefinite, one sometimes writes $M \geq 0$ and if $M$ is positive-definite one writes $M > 0$ .^[1]The notion comes from functional analysis where positive definite matrices define positive operators.

For arbitrary square matrices $M, N$ we write $M\geq N$ if $M-N \geq 0$ , i.e. $M - N$ is positive semi-definite. This defines a partial ordering on the set of all square matrices. One can similarly define a strict partial ordering $M > N$ .

1.	Every positive definite matrix is invertible and its inverse is also positive definite.^[2] If $M \geq N > 0$ then $N^{-1} \geq M^{-1} > 0$ .^[3]
2.	If $M$ is positive definite and $r > 0$ is a real number, then $r M$ is positive definite.^[4] If $M$ and $N$ are positive definite, then the sum $M + N$ ^[4] and the products $M N M$ and $N M N$ are also positive definite. If $M N = N M$ , then $M N$ is also positive definite.
3.	If $M = (m i j) > 0$ then the diagonal entries $m i i$ are real and positive. As a consequence tr $(M) > 0$ . Furthermore $\| m_{ij} \| \leq \sqrt{m_{ii} m_{jj}} \leq \frac{m_{ii}+m_{jj}}{2}$ and thus $\max \|m_{ij}\| \leq \max\|m_{ii}\|$ ^[5]
4.	A matrix $M$ is positive semi-definite if and only if there is a positive semi-definite matrix $B$ with $B 2 = M$ . This matrix B is unique^[6], is called the square root of M, and is denoted with $B = M 1 / 2$ (the square root B is not to be confused with the matrix L in the Cholesky factorization M = LL*, which is also sometimes called the square root of M). If $M > N > 0$ then $M 1 / 2 > N 1 / 2 > 0$ .
5.	If $M, N > 0$ then $M\otimes N > 0.$ (Here $\otimes$ denotes Kronecker product.)
6.	For matrices $M = (m i j)$ and $N = (n i j)$ , write M ˆ N for the entry-wise product of $M$ and $N$ , i.e. the matrix whose $i, j$ entry is $m i j n i j$ . Then M ˆ N is the Hadamard product of $M$ and $N$ . The Hadamard product of two positive-definite matrices is again positive-definite and the Hadamard product of two positive-semidefinite matrices is again positive-semidefinite (this result is often called the Schur product theorem).^[7] Furthermore, if M and N are positive-semidefinite, then the following inequality, due to Oppenheim, holds: $\det(M\circ N) \geq (\det N) \prod_{i} m_{ii}.$ ^[8]
7.	Let $M > 0$ and $N$ Hermitian. If $MN+NM \geq 0$ ( $M N + N M > 0$ ) then $N\geq 0$ ( $N > 0.$ )
8.	If $M,N\geq 0$ are real matrices then $\text{tr}(MN)\geq 0.$
9.	If $M > 0$ is real, then there is a $δ > 0$ such that $M\geq \delta I$ where $I$ is the identity matrix.

Non-Hermitian matrices

A real matrix M may have the property that x^TMx > 0 for all nonzero real vectors x without being symmetric. The matrix

$\begin{bmatrix} 1 & 1 \\ -1 & 1 \end{bmatrix}$

satisfies this property, because for all real vectors $x = (x 1, x 2) T$ such that $x \ne 0$ ,

$\begin{bmatrix} x_1 & x_2 \end{bmatrix} \begin{bmatrix} 1 & 1 \\ -1 & 1 \end{bmatrix} \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} = x_1^2 + x_2^2 > 0 .$

In general, we have x^TMx > 0 for all real nonzero vectors x if and only if the symmetric part, (M + M^T) / 2, is positive definite.

The situation for complex matrices may be different, depending on how one generalizes the inequality z^*Mz > 0. If z^*Mz is real for all complex vectors z, then the matrix M is necessarily Hermitian. So, if we require that z^*Mz be real and positive, then M is automatically Hermitian. On the other hand, we have that Re(z^*Mz) > 0 for all complex nonzero vectors z if and only if the Hermitian part, (M + M^*) / 2, is positive definite.

In summary, the distinguishing feature between the real and complex case is that, a bounded positive operator on a complex Hilbert space is necessarily Hermitian, or self adjoint. The general claim can be argued using the polarization identity. That is no longer true in the real case.

There is no agreement in the literature on the proper definition of positive-definite for non-Hermitian matrices.

Notes

^ This may be confusing, as sometimes nonnegative matrices are also denoted in this way. A common alternative notation is $M \succeq 0$ and $M \succ 0$ for positive semidefinite and positive definite matrices, respectively.
^ Horn & Johnson (1985), p. 397
^ Horn & Johnson (1985), Corollary 7.7.4(a)
^ ^a ^b Horn & Johnson (1985), Observation 7.1.3
^ Horn & Johnson (1985), p. 398
^ Horn & Johnson (1985), Theorem 7.2.6 with k = 2
^ Horn & Johnson (1985), Theorem 7.5.3
^ Horn & Johnson (1985), Theorem 7.8.6

References

Horn, Roger A.; Johnson, Charles R. (1985), Matrix Analysis, Cambridge University Press, ISBN 978-0-521-38632-6 .
Rajendra Bhatia. Positive definite matrices. Princeton Series in Applied Mathematics, 2007. ISBN 978-0691129181.

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Positive-definite matrix

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