The answer is 30 moles.
30 moles
4 moles
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
11,2 moles carbon dioxide are obtained.
6 moles COULD be produced
30 moles
0,3 moles of nitrogen reacted.
6 moles
3.50 W 21.80 x 1/14th
X = 0.489 moles of AgCl produced
30 moles
4 moles
4 moles
.033 mol H2
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
8 mol
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3