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Answered 2011-01-13 11:45:01

Three blind mice. See how they run.

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"Three blind mice, see how they run", which is a line from a children's song.


3 blind mice


To complete the square for a quadratic ax² + bx + c = 0 1) Divide through by the coefficient of the x² term to get x² + b/a x + c/a = 0; let B = b/a; let C = c/a; the equation is now x² + Bx + c = 0 2) Complete the square by taking half of B and adding it to x and squaring: (x + B/2)² 3) Expanding this gives: (x + B/2)² = x² + Bx + (B/2)² → x² + Bx = (x + B/2)² - (B/2)² 4) Substitute this in the original equation to give: x² + BX + C = (x + B/2)² - (B/2)² + C 5) This can now be solved as (x + B/2)² - (B/2)² + C = 0 → (x + B/2)² = (B/2)² - C For m² - 6m - 7 = 0, completing the square gives: (m - 6/2)² - (6/2)² - 7 = 0 → (m - 3)² - 9 - 7 = 0 → (m - 3)² -16 = 0 → (m - 3)² = 16 → m - 3 = ±4 → m = 3 ± 4 → m = 7 or -1.


In y=mx + b form, y = (-3/4)x - 3 - Found the slope (m) to be -3/4 - Substituted slope and a point into y = mx + b to find y-intercept (b). - b = - 3 , Substitute b and m into y=mx+b


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the equation is in the correct format [y = m*x + b]. m is slope, b is y intercept. So m = 1/3, and b = 2. Slope is 1/3. Any other line which has a slope of 1/3 will be parallel to this line.


3 blind mice see how they run.


3 blind mice see how they run.


a = 2b - 2 c = b + 3 so 2b - 2 + b + b + 3 = 25 that is, 4b + 1 = 25 ie 4b = 24 and so b = 6 then a = 2b - 2 = 12 - 2 = 10 and c = b + 3 = 6 + 3 = 9 So the three sides are 10m, 6m and 9m.


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(-2,7),(3,-8) first you find the slope: m=y2-y1 _____ x2-x1 m=-8-7 _____ 3+2 m=-3 then you find the y-intercept: y=mx+b 7=((-3)(-2))+b 7=6+b -6 -6 1=b so its y=-3x=1


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ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab


5x-11y=25 No^ NO^ The real answer: y=mx+b Y = a y value, x = an x value. M=slope, b=y intercept. therefore, if a slope (m) is 3, plug 3 in for m, and if (-3) is the yintercept, plug (-3) in for b. y=5x+(-3) the +(-) can be changed to a minus, so: y=5x-3


import java.io.*; public class matrixmul { public static void main (String args[]) { try { BufferedReader e = new BufferedReader(new InputStreamReader(System.in)); int m,n; int c[][] = new int[3][3]; int b[][] = new int[3][3]; int d[][] = new int[3][3]; for ( m = 0 ; m < 3; m++ ) { for (n = 0; n < 3 ;n++) { System.out.println("-- Enter A number in row# "+(m+1)+" & # "+(n+1)+" column --" ); c[m][n] = Integer.parseInt(e.readLine()); } } System.out.println(" ----- First Matrix ----"); for ( m = 0 ; m < 3; m++ ) { for (n = 0; n < 3 ; n++) { System.out.print(c[m][n]); } System.out.println(); } for ( m = 0 ; m < 3; m++ ) { for (n = 0; n < 3 ;n++) { System.out.println("-- Enter A number in row# "+(m+1)+" & # "+(n+1)+" column --" ); b[m][n] = Integer.parseInt(e.readLine()); } } System.out.println(" ----- Second Matrix ----"); for ( m = 0 ; m < 3; m++ ) { for (n = 0; n < 3 ; n++) { System.out.print(c[m][n]); } System.out.println(); } for ( m = 0 ; m < 3; m++ ) { for (n = 0; n < 3 ;n++) { d[m][n] = d[m][n]+(b[m][n]*c[m][n]); } } System.out.println(" ----- Multiplication of above matrix ----"); for ( m = 0 ; m < 3; m++ ) { for (n = 0; n < 3 ; n++) { System.out.print(" "+d[m][n]); } System.out.println(); } } catch (Exception e){} } }


3 blind mice ( see how they run)


3 Blind Mice - See How They Run


3 blind mice see how they run.


Assuming it's a straight line (y=mx+b or Ax+By+C=0) then we will: 1. Find the slope of the line using the slope formula. y2-y1/x2-x1=m (keep in mind that the bigger value does not necessarily have to be y2 or x2, you will end up with the same "m" value regardless) 2-3/3-9=m -1/-6=m 1/6=m 2. Calculate vertical shift (b value). Sub a point into the equation y=(1/6)x+b (It does not matter which point you use, again, either one will work) 2=(1/6)(3)+b (I used the point (3,2) in this instance) 2=(3/6)+b 2=(1/3)+b 2(3)=b b=6 3. Write the equation. y=(1/6)x+6


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Trasnlate m + b into words for algebra


the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m


(2,4) and (-4,8) y=mx+b 4=m(2)+b 4=2m+b b=y2-y1 /x2-x1 b = (8-4)/(-4-2) b=4/-2 b=-2 4=2m+-2 6=2m 3=m So your y=mx+b equation would be: y=3x+-2



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