4 fingers and 1 thumb on a hand
There are 16 possible outcomes, each of which is equally likely. So each has a probability of 1/16 HHHH: X = H*T = 4*0 = 0 HHHT: X = H*T = 3*1 = 3 HHTH: X = H*T = 3*1 = 3 HTHH: X = H*T = 3*1 = 3 THHH: X = H*T = 3*1 = 3 HHTT: X = H*T = 2*2 = 4 HTHT: X = H*T = 2*2 = 4 HTTH: X = H*T = 2*2 = 4 THHT: X = H*T = 2*2 = 4 THTH: X = H*T = 2*2 = 4 TTHH: X = H*T = 2*2 = 4 HTTT: X = H*T = 1*3 = 3 THTT: X = H*T = 1*3 = 3 TTHT: X = H*T = 1*3 = 3 TTTH: X = H*T = 1*3 = 3 TTTT: X = H*T = 0*4 = 0 So, the probability distribution function of X is f(X = 0) = 1/16 f(X = 1) = 4/16 = 1/4 f(X = 2) = 6/16 = 3/8 f(X = 3) = 4/16 = 1/4 f(X = 4 = 1/16 and f(X = x) = 0 for all other x
1 2 3 4 h h h h h h h t h h t h h h t t h t h h h t h t h t t h h t t t t h h h t h h t t h t h t h t t t t h h t t h t t t t h t t t t
f i f t h
f i f t h
The two American doll codes are 1 4 7 j - 4 f a e - h 7 a g , the next code is r 3 9 4 - e f t h - 4 4 a g
F F g h u y t h f s j
T. F. H. Allen has written: 'Toward a unified ecology' -- subject(s): Ecology, Philosophy
No word contains only the letters f t and h. A word that contains all 3 in that order is faith.
4: h/h, h/t, t/h & t/t
12..... h+1, h+2, h+3, h+4, h+5, h+6, t+1, t+2, t+3, t+4, t+5, t+6,
4 coins tossed could have the following patterns T T T T T T T H, T T H T, T H T T, H T T T T T H H, T H T H, T H H T, H H T T, H T H T, H T T H H H H T, H H T H, H T H H, T H H H H H H H Odds of 2H&2T = 6/16 = .375
there could be five possible outcomes: t= tails h= heads t t t t 4 tails t t t h 3 tails 1 head t t h h 2 tails 2 heads t h h h 1 tail 3 heads h h h h 4 heads