A car traveling at 92 kmh strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.85 m. What was the average acceleration of the driver during the collision?
92km/h = 41*5/3*3 =205/9m/s
v = 205/9 m/s
u = 0m/s
s = 0.85m = 85/100m
a = ?
v2 = u2 + 2as
=> 2052/81 = 2 * a * 85/100
=>a = -0.9766m/s2
The average acceleration of an object is equal to the instantaneous acceleration of that object if the acceleration is constant (i.e. linear when graphed). However, when there is not constant acceleration, there is no guarantee that the average acceleration is equal to the instantaneous acceleration (i.e. non-linear when graphed).
Suppose that an object is traveling along a straight line Suppose that its velocity function is given by vt equals 4t2 -8t where t is in seconds Find the objects average acceleration along the time?
A car traveling at 25 meters a second speeds up to 40 meters a second over a period of 15 seconds what is the average acceleration of the car?
Answer Acceleration = v2 - v1 .........................time Average Acceleration requires you to average the the initial velocity of your trials and the ending velocity of your trials. You must also find the average for your time trials. Once you achieve these numbers, just plug them into the above formula and you can solve for average acceleration.