128 liters
The volume percent concentration of hexane in a solution made by mixing 50.0 mL of hexane with 1.0 L of pentane is 4.8
ONe word term is 'Dissolution'. Or Making a solution.
The value is 33,3 %.
Hexadecimal is a way of representing numbers! It is not a substance and so cannot form a solution.
when you form a solution by mixing everything evenly, the solute will what into the solvent
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
The volume percent concentration of hexane in a solution made by mixing 50.0 mL of hexane with 1.0 L of pentane is 4.8
ONe word term is 'Dissolution'. Or Making a solution.
No. The reulting concentration (percent) must be between the two components. So, with the two acids you are mixing, you cannot get an acid that is less than 10% or more than 40%
You can make your own solution by mixing 40 percent water, 40 percent rubbing alcohol and 20 percent dish soap into a spray bottle.
The value is 33,3 %.
Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.
Hexadecimal is a way of representing numbers! It is not a substance and so cannot form a solution.
salt and water
Yes, it is a solution.
Let M equal the gallons of the 90% mixing solution. Let F equal the gallons of the final solution. So:90 + M = F.Also, the number of gallons of pure antifreeze in the final will equal the sum of the gallons of antifreeze in the two mixing parts:Original solution: ( 90 gal )*(0.15) = 13.5 gal [0.15 represents 15%]Mixing solution: M*0.90Final solution: F*0.80So 13.5 + M*0.90 = F*0.80Now you have 2 linear equations and 2 unknowns, you can solve for M & F, using your favorite method: M = 585 and F = 675. Add 585 gallons of the 90% to get 675 gallons of 80% solution.
when you form a solution by mixing everything evenly, the solute will what into the solvent