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8 is the new volume of the gas.

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Mia Herzog

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2y ago
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13y ago

V1/T1 = V2/T2 (Charles' Law)

T is in Kelvin. Celsius temp plus 273.15 = K

T1 = 14 +273

= 287 K

T2 = 29 + 273

= 303 K

4.5 / 287 = V2 / 303

V2 = 4.75 L

= 4.8 L

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14y ago

pV = nRT

p = pressure

V = volume

n = number of moles

R = gas constant

T = temperature (in Kelvin)

In this case, the number of moles remains the same, as does the gas constant (it IS a constant, after all) and pressure. The only things changing are the volume and temperature. This simplifies the equation to:

4 cubic meters gas = 200 K (-73 degrees celsius)

Therfore:

200K/4 = 400K/x

x = 8 cubic meters

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10y ago

A sample of argon gas at a pressure of 715 mmHg and a temperature of 26 degrees Celsius occupies a volume of 8.97 L. If the gas is heated at a constant pressure of 71 degrees Celsius, what will be the volume of the gas sample (in liters)

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10y ago

The gas law states that P1V1/T1 = P2V2/T2 where T is Kelvins, that is C + 273

In your example we have

745(5.3)/299 = P2(5.3)/363

P2 = 904.5 mm Hg

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15y ago

I am trying to figure this out too

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14y ago

60 cubic meters.

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9y ago

8 is the new volume of the gas.

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14y ago

a+

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13y ago

PAr=.826atm

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Q: 30 cubic meters of argon gas is kept under constant pressure the gas is heated from 10.0 degrees Celsius to 293 degrees celsius what is the new volume of the gas?
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