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It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.
Acceleration = (change in speed) divided by (time for the change) = (9/3) = 3 m/s2
66.7 m/s2
It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.
Average acceleration over a certain time period is the difference in velocity, divided by the time. In this case, (4-2)/W.
-6.38715
3 ms-2
The idea is that you should: a) Calculate the change in velocity. b) Divide this change by the time. This gives you the average acceleration over the 20 seconds, in this case.
Acceleration(a) = [final velocity(v) - initial velocity(u)] / time(s) Algebrtaically a = [ v - u ] / s A negative result indicates deceleration a = [20 - 40 ]= / 4 a = [-20] / 4 a = -5 m/s^(2) This is negative which matches the question of slowing down/deceleration.
Acceleration = delta velocity/delta time a = 70 m/s/35 seconds = 2 m/s2 ------------
Acceleration = (change in speed) divided by (time for the change) = (9/3) = 3 m/s2
If the 0.75 refers to seconds, then his acceleration is -66.66... (repeating) metres per second^2.