Silver bar 0.125 meter long is subjected to a temperature change from 200C to 100C What will be the length of the bar after the temperature change?

Answer 1

The coefficient of linear expansion (Kl ) for silver is 0.0000189.

I = LKl (To - Tf )

I = 1.4 m × 0.0000189 × (55°C - 10°C)

I = 1.4 × 0.0000189 × 45

NOW=A silver bar 0.125 meter long is subjected to a temperature change from 200 degrees celsius to 100 degrees celsius what will be the length of the bar after the temperature change?

I=LKI (T0-Tf)

=>I=0.125×0.0000189×(200-100)

=>I=0.00023625

Answer 2

To calculate the linear expansion or contraction of an object it is necessary to use the following equation:A

Lc/Lo = α x Tc

Where:

Lc = Change in length (m)

Lo = Original length (m)

α = Linear Temperature Expansion Coefficient (10-6 m/K)

Tc = Change in temperature (K)

The Linear Temperature Expansion Coefficient of SilverA = 18.9x10-6 m/K

Rearranging the equation to make Lc the subject yields:

Lc = α x Tc x Lo

Lc = 18.9x10-6 x -100 x 0.125

Lc = -0.00023625

Change in length of bar = -0.00023625 m

New Length of bar = 0.125 - 0.00023625

New Length of bar = 0.12476375 m

Answer 3

L2 = L1 + Delta L = L1 + ( L1) ( CLEXP ) ( Delta T )

L2 = 0.125 m + ( 0.125 m ) ( 19.5 x 10^-6 m / m - C ) ( -100 C )

L2 = 0.125 m - 0.000244 m = 0.124756 m <----[ Answer ]---

Answer 4

0.24764 meter

Answer 5

0.124764 meter

Answer 6

0.124764 meter

Answer 7

not sure: 0.124764 m