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Answered 2017-04-03 15:38:12
This sodium hydroxide solution has a molarity of 0,25.
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This molarity is approx. o,89.
The molarity is 0,041
If 1,1 is grams the molarity is 0,317.
Molarity is a measurement of concentration. The molarity of a solution tells a chemist how much of an element or compound is dissolved in a certain amount of the solution.
This molarity is 13 M; but this solution doesn't exist.
Molarity = moles of solute/liters of solution Molarity = 7 moles solute/2 Liters solution = 3.5 M ======
Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================
Molarity = moles of solute/volume of solution M = 0.25 moles/0.50L = 0.5M
The molar mass of KMnO4 is 158,3415 g.The molarity of this solution is 0,1 M.
molarity = moles/litre [solution] = 6 mol/2 L [solution] = 3 M
This molarity is 0,207 mol.
The molarity is 0.718 moles/litre.
Molarity=no. of moles of solute/vol of solution in(L) molarity=0.4/9.79=0.04086 mol L-1=0.04086 M.
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity
Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.
The answer is 0,625 moles.
The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.
Molarity is the amount of a compound (in this case the solute) related to a known volume of solution.
Molarity is defined as moles/liters. So the concentration of your solution (your answer) is 1 M. You have a one molar solution (mol/L).
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
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