Top Answer

This sodium hydroxide solution has a molarity of 0,25.

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1This molarity is approx. o,89.

The molarity is 0,041

If 1,1 is grams the molarity is 0,317.

Molarity is a measurement of concentration. The molarity of a solution tells a chemist how much of an element or compound is dissolved in a certain amount of the solution.

This molarity is 13 M; but this solution doesn't exist.

Molarity = moles of solute/liters of solution Molarity = 7 moles solute/2 Liters solution = 3.5 M ======

Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================

Molarity = moles of solute/volume of solution M = 0.25 moles/0.50L = 0.5M

The molar mass of KMnO4 is 158,3415 g.The molarity of this solution is 0,1 M.

molarity = moles/litre [solution] = 6 mol/2 L [solution] = 3 M

This molarity is 0,207 mol.

The molarity is 0.718 moles/litre.

Molarity=no. of moles of solute/vol of solution in(L) molarity=0.4/9.79=0.04086 mol L-1=0.04086 M.

31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity

Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.

The answer is 0,625 moles.

The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.

Molarity is the amount of a compound (in this case the solute) related to a known volume of solution.

Molarity is defined as moles/liters. So the concentration of your solution (your answer) is 1 M. You have a one molar solution (mol/L).

Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1

Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.

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