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A triangle has a base of 7 ft and an altitude of 15 ft Find its area to the nearest tenth?
Wiki User
∙ 14y ago
Area of a triangle = (base x Height)/2 = 7 ft x 15 ft/2 = 105/2 sq ft= 52.5 sq ft
Wiki User
∙ 14y ago
Charlz andrei Eugeni...
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The perimeter of an equilateral triangle is 32centimeters find the length of an altitude of the triagle to the nearest tenth of a centimeter?
Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm. If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have, sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides) (32/3 cm)sin 60⁰ = altitude 9.2 cm = altitude
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in triangle def side de equals 5 and angle d equals 55 find fe
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The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
The perimeter of an equilateral triangle is 32centimeters find the length of an altitude of the triagle to the nearest tenth of a centimeter?
Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm. If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have, sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides) (32/3 cm)sin 60⁰ = altitude 9.2 cm = altitude
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In triangle DEF DE equals 5 and measure of angle D is 55 degree's find Fe to the nearest tenth?
in triangle def side de equals 5 and angle d equals 55 find fe
A circle has a circumference of 110.6 mm Find its diameter to the nearest tenth?
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