A male who is colorblind marries a heterozygous womanWhat percent of their total children will be color-blind?

Answer 1

NOW. Colourblindness we will assume, is a Sex-Linked Disorder. Hence, the sex chromosomes are involved in determinig the phenotypes of the children. XY --male XX--female XbY--colourblind male XBXb --normal female Cross: (parents) Xby * XBXb F1 progeny/offspring XBXb, XbXb, XBY, XbY 50 % of the children will be colourblind. This is a very simple question. You also need to clarify within the question if it is sex linked or autosomal.

Answer 2

as previously stated, there is a 100% certainty that the son of a color blind mother will be color blind.

The chances of any daughter being color blind are a bit more complicated.

If the father is color blind, and the mother is as well, there is a 100% chance of the daughter being color blind too.

If the father is not, then the daughter of a color blind mother will not be color blind, though there is a 100% certainty that she will be a carrier, and so there is 50/50 chance that any of her sons will be (actually slightly more, if we account for the chance that her future partner may be color blind as well).

If we accept that the prevalence of color blindness in the male population is about 5%, then the likelihood of any daughter from a color blind mother and some random father is about 5% as well.

Answer 3

Yes the child will be red/green color blindif shown through a punnett square so its highly likely this will happen

There is a 100% chance their child/children will be red-green colorblind

Answer 4

The son will be color-blind. Color-blindness is a recessive trait found on the X-chromosome, and for someone to be color-blind all present X-chromosomes MUST have the recessive trait. Therefore, a son from a color-blind mother (who receives the trait from his mother on the X-chromosome) will always be color-blind, regardless of the state of the father (who can only give his son a Y-chromosome).

This is why color-blindness is more commonly found in men than in women, since men only require one X while women must have two X carrying the trait present. All of the daughters of this couple will be carriers of color-blindness, but will not be color-blind.

Answer 5

If a female who does not carry the color blindness gene has children with a color blind male, none of their offspring will be colorblind. Their daughters have a 50 percent chance of carrying the color blindness allele, and their sons will not carry it.

Answer 6

The probability of these two having a color blind son is close to 0 (though it is still possible). This is because color blindness is a recessive gene while normal vision is the dominant gene. Even though the son might not be color blind, he will still carry the color blind gene.

*The above answer is wrong....

The Probability of the son being color blind is 100%. The color blind gene is recessive and is located on the X chromosome. Mom has two X's and the dad: XY. The dad is not a carrier (and cant be) because he only has one X, and it can't carry the gene or he would express it.

The mom passes an X to her son and the dad passes his Y. The son has to have a color blind X because the mom is colorblind and the dad has no effect on whether or not his son is colorblind. Therefore, the son will be colorblind.

Answer 7

Woman carrier genotype = XCXc (where XC is the normal allele, and Xc is the affected allele)

Man who is not color blind must have genotype = XCY

Possible genotypes of children are:

XCXC , XCY, XcXC , and XcY

only one possible (out of 4) will be color blind (and only if they have a son). Therefore, there is a 25% chance that the child will be color blind.

Answer 8

50/50 because the child gets 26 chromozones from each parent so the chances are 50/50.

Answer 9

50%. It depends on which copy of the X chromosome the boy receives from the mother. Also, the father's color blindness doesn't matter at all for male children.

Answer 10

25% only they have a son