A ideal machine would have an efficiency of 100 percent. For this to be possible, the amount of energy output by the machine would equal the amount of energy input. Because all machines have physical parts, some energy is lost to friction, heat dissipation, or other factors, so no machine can be an ideal machine.
Ideal would be 100 percent. But you'll never get it. Due to the principle of conservation of energy, energy efficiency within a closed system can never exceed 100%. At a loutspeaker you have electrical Voltage as input and sound pressure as output. The efficiency of the loudspeaker is really only 1 percent.
... of 1, or 100%.
your mom !lol xD
One possibility is to finalise an academic document such as a dissertation.
If two ideal sources of unequal voltage are connected in parallel the higher voltage will provide a majority of the current (a two percent difference in voltage would provide an additional 5% of the current) and (in the case of batteries) the larger would provide charging current, quickly draining it.
no its a personal machine
its a compound machine
Ideal filters are not realizable because it would require a impulse response that extends from minus infinity to plus infinity, and it would be also a noncausal system. It may be proved on the frequency domain using the Paley-Wiener Criterion, which states that a square integrable magnitude response function |H(f)| is physically realizable if \int_{-\infty}^{+\infty} \frac{| \log_e |H(f)| |}{1+f^2} df < \infty Any ideal filter would require H(f) to have magnitude equals zero in a bandwidth and that would make | \log_e |H(f)| | infinitely large and the condition above would not hold.
an ideal machine
No, an efficiency greater than one would not be possible, since that would violate a very fundamental law of physics: conservation of energy. The efficiency of an "ideal machine" would be one, in many cases; the efficiency of an ideal Carnot engine would be less than one.
No, there is not such thing as an ideal machine; it's just an idea.
No heat loss = maximum output. There would be no loss of energy, which is an ideal condition.
In ideal machine input is equal to output . The efficiency of ideal machine is 100% . In real machine input is not equal to output .The efficiency of ideal machine in not 100% . In ideal machine there is no lose of energy . In real machine there is lose of energy . In real machine there is no friction . While in real machine there is friction .
In an ideal frictionless system, the work input equals the output and force. Your Welcome!!!
An ideal machine can reach 100% efficiency as there is no friction or other restraints involved, whereas a real machine can never reach 100% efficiency.
In ideal machine input is equal to output . The efficiency of ideal machine is 100% . In real machine input is not equal to output .The efficiency of ideal machine in not 100% . In ideal machine there is no lose of energy . In real machine there is lose of energy . In real machine there is no friction . While in real machine there is friction .
In an ideal frictionless system, the work input equals the output and force. Your Welcome!!!
The efficiency of a machine is usually expressed as a percentage. The ideal efficiency of a machine is 100-percent.Another AnswerThere are no units of measurement for efficiency, because you are comparing like with like: output power divided by input power.
No physical machine is ideal. Friction is always a loss of energy.
In practical there is no machine which have efficiency 100%,i.e. output work = input work. But an ideal machine have efficiency of 100%, for an example a Carnot's heat engine. The efficiency of this engine is 100% but it is an ideal situation. As an expression of efficiency it is equal to W/Q, where W is work done by the system and Q is heat put into the system. For efficiency =1 ,i.e.100% if and only if W=Q and vice verse.