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An object is located 51mm from a diverging lens the object has a height of 13mm and the image height is 3.5 how far in front of the lens is the image located?
Wiki User
∙ 11y ago
The rays of light going through the dead centre are not deviated. So the angle from the top of image to lens centre is the same as for top of object to lens centre. So height is proportional to distance. So 13/51 = 3.5/dist giving distance=3.5x51/13 = about 13.73mm
Wiki User
∙ 11y ago
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An object 51 mililmeters from a diverging lens the object has a height of 13 milimeters and the image height is 3.5 milimeters how far in front of the lens is image located?
Pizza
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?
Using the magnification equation m = - v / u. The image should be 13.73 mm in front of the lens
An object is located 51 millimeters from a diverging lensthe object has a height of 13 millimeters and thye image height is 3.5 millimetershow far in front of thelens is the image located?
The relation between the distance and height of an object and the image goes like this:L1/H1=L2/H2where L1 and H1 is the Length of the object from the lens and H1 is the height of the object respectively. Same goes for L2, H2 except these are for the image of the same object.If you put values in the above formula, the distance of the image from the lens comes out to be 13.73mm
An object is 5 millimeters high is located 15 millimeters in front of a plane mirror how far from the mirror is the image located?
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An object 51 mililmeters from a diverging lens the object has a height of 13 milimeters and the image height is 3.5 milimeters how far in front of the lens is image located?
Pizza
An object is 51 millimeters from a diverging lens the object has a height of 13 millimeters and then image height is 3.5 millimeters How far in front of the lens is the image located?
13.7 millimeters
An object is located 51 millimeter from a diverging lens the object has a height of 13 millimeter and the image heightg is 3.5 millimeters how far in front of the lens is the image located?
7
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?
Using the magnification equation m = - v / u. The image should be 13.73 mm in front of the lens
An object is located 15millimeters from a diverging lens the object has a height of 13 mm and the image height is 3.5 mm how far in front of the lens is the image located?
Using the expression v/u = Image size / object size we can find the value of v. v = 15 * 3.5/13 = 4 (nearly) So approximately at a distance of 4 mm in front of the lens the image is located on the same side of the object.
If an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the len what is the height of the image?
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An object is located 51 millimeters from a diverging lens the object has a height og 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?
hi/ho = di/do di = dohi/ho di = (51mm)(3.5mm)/(13mm) di = 14mm * rounded to 2 significant figures The image would be 14mm in front of the lens.
An object located 51 millimeters from a diverging lens the object is 13 millimeters high and the image 3.5 millimeters how far in front of the lens is the image located?
13.7 millimeters
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image is 3.5 meters how far in front of the lens is the image located?
13.7 millimetersThis answer is correct, but the formula is most important.The formula is:Hi = height of imageHo = height of objectSi = Distance of image from lensSo = Distance of object from lensYou are trying to find Si, so that is your unknown.Here is your formula: Hi/Ho = Si/SoOr in this case: 3.5/13 = Si/51The rest is basic algebra.Good luck!You can use the ratio equation; (Image Height)/(object height) = - (image location)/(object location) In your case you will get a negative location which means the image is on the same side of the lens as the incoming light.
An object is located 51 millimeters from a diverging lensthe object has a height of 13 millimeters and thye image height is 3.5 millimetershow far in front of thelens is the image located?
The relation between the distance and height of an object and the image goes like this:L1/H1=L2/H2where L1 and H1 is the Length of the object from the lens and H1 is the height of the object respectively. Same goes for L2, H2 except these are for the image of the same object.If you put values in the above formula, the distance of the image from the lens comes out to be 13.73mm
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