They are inverses. For any numbers a, b, and c if: a + b = c then: a = c - b and b = c - a In words, addition is raising the value of a number by counting higher, (1, 2, 3, ...). Subtraction is the inverse (you count down 3, 2, 1, ...).
literal words of 1 to 100 does not contain a or b or c......
a + (b + c) = (a + b) + c for any [ordinary] numbers a, b, and c.
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern B--C-B-C-. That is, nine letter words with 1st letter B and 4th letter C and 6th letter B and 8th letter C. In alphabetical order, they are: blackbuck
If you do not know whether a < c or c < a then it is much simpler in words. It is "b lies between a and c". Mathematically, it is min[0.5(a + c -|a - c|)] < b < min[0.5(a + c +|a - c|)].If you do know that a < c then it is simply a < b < c.
For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)
There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.
No. A can be independent of both B and C and this doesn't give use any information about the relationship between B and C.
It is impossible to give any decimal/numeric value if we are not given the values of at least one variable, so the answer is B + B + B + C + C + C.
The distributive property OF MULTIPLICATION over addition is a*(b + c) = a*b + a*c for any numbers a, b and c.
a - b = c c + b = a
There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.