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Area of pipe when thickness of wall inner radius of pipe and length of pipe is given?
Wiki User
∙ 13y ago
For a pipe of uniform radius and thickness, I believe the total surface area would be the Outside surface + Inside surface+ 2 times the surface of the ends. The inside radius(rinner), pipe thickness (t), and pipe length (L) are given.
So you only need to find the outside radius (Rout) and then all areas can be calculated.
The outside radius should be Rout=rinner +t. And note the perimeter of a circle is 2*pi*Radius and area of an annular region (in this case the ends of the pipe) is A= pi*(Rout2 - rinner2)
For the outer pipe surface: Aout=2*pi*(Rout)*L
For the inner pipe surface: Ainner=2*pi*(rinner)*L
For each pipe end: Aend= pi*(Rout2 - rinner2)
So the total surface area of the pipe would be: Aout+ Ainner+2* Aend
Or: Atotal =2*pi*(Rout)*L+2*pi*(rinner)*L+ 2*pi*(Rout2-rinner2)
= pi*[ 2*L*(Rout + rinner)]+(Rout2 - rinner2)
= 2*pi*[ L*( rinner +t + rinner)]+(( rinner +t )2 - rinner2)]
=2*pi*(t+L)(t+2*rinner)
Hopefully that is correct and helps.
Wiki User
∙ 13y ago
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