What is the volume of 110g of CO2 g at STP?

Answer 1

At STP, Standard Temperature and Pressure, one mole of gas takes up 24dm3 of volume. One mole of nitrogen weighs 14g, so in 888g there are 63.4 moles of nitrogen. This takes up a volume of 63.4 x 24 = 1522.3dm3.

Answer 2

56.1 L

PV=nRT (my Chemistry teacher taught me to pronounce it Pivvy equals Nert to remember the formula.)

set it up so that V=(nRT)/P

n= number of moles of CO2 --> convert 110g CO2 to moles (the answer is around 2.499 moles)

R= 0.0821 (liters X atm)/(mol X K)

T = 273.15K at STP

P= 1 atm

Plug all of those numbers into V=(nRT)/P and you get 56.1 L

Answer 3

Density of CO2 is 1.977 g/L at 1 atm and 0oC , so 88.4 g takes

88.8(g) / 1.977(g/L) = 44.7 L at 1 atm and 0oC .

At any other higher temperature this value should be corrected by multiplying the answer with the T(C)factor :

(273 + T(oC)) / (273)

Answer 4

Number of Moles= Mass/ RAM

n= 88/44

n=2

volume= 2/22.4

Volume=0.089286 dm3

{| |- | 0.089286

0.089286

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Answer 5

You find the answer by mulitplying the 8 moles by 22.4, L/mol, which is the volume of any one mole of gas at STP. So the answer is 179.2 L

Answer 6

At 25 0C and 1 atmosphere the molar gas volume is 24,465 litres.

Answer 7

The density of carbon dioxide at STP is 0,769 g/L.

Answer 8

22.41 liters.

Answer 9

456g