what is the balanced equation for Rubidium metal reacting with
Rubidium metal would react with iodine to make rubidium iodide , according to the equation: 2 Ru + I2 -> 2 RuI
2Rb + H2 --> 2RbH The product is rubidium hydride.
It is potassium chloride + iodine = potassium iodine + chloride.
RbOH + HClO4 -> RbClO4 + H2O Products are rubidium chlorate and water.
2Rb + 2H2O -------> 2RbOH + H2
The equation is 2 RbOH + H2SO4 -> Rb2SO4 + 2 H2O.
Balanced: H2 + I2 ----> 2 HI
Yes. Rubidium is an alkali metal in the sodium group. It will react with iodine to form rubidium iodide:- 2Rb+ I2 -> 2RbI
The rubidium iodide is RbI.
Rubidium iodide is an ionic compound.
2NI3 -----> N2 + 3I2
2Cs (s) + I2 (l) = 2CsI (s)
Calcium + Iodine --> Calcium iodide 1 Ca + 1 I2 --Δ--> 1 CaI2
I2 + 2Na2S2O3 = 2NaI + Na2S4O6
It does so in 1:3 ratio; hence the formula AlI3.Aluminum iodine is another example of iodine
The word equation for the reaction of rubidium with water is rubidium + water --> rubidium hydroxide + hydrogen. Rubidium is a metal that reacts very quickly and fiercely, even explosively with water.
Ch4(oh)2 + i4 --> ci4 + 2h(oh)3
I2(aq)+2Na2S2O3(aq)---------------->2NaI(aq) + Na2S4O6(aq)
H2,g + I2,s --> 2HIg
3IBr + 4NH3 --> NI3 + 3NH4Br
Cl2 + 2NaI --> 2NaCl + I2
The chemical equation for iodine is I
you have to write... 2KI + Cl2 = 2KCl + I2
Aluminium + Iodine ----> Aluminium iodide 2 Al + 3 I2 ----> 2 AlI3
2Zn + Pb(No3)2 --> 2ZnNO3 + Pb
Rubidium + water --> rubidium hydroxide + hydrogen 2Rb(s) + 2H2O(l) --> 2RbOH + H2(g)
The chemical reaction is: Br2 + 2 NaI = 2 NaBr + I2
no...a skeleton is just the equation before it is actually balanced,
A balanced chemical equation has correct placed coefficients and a representative chemical equation need these coefficients.
The balanced equation for the reaction between Iodine and Hydrogen is: H2 + I2 --> 2HI The ratio of I2 to HI is 1:2 Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide
What is the balanced equation for Ch3COOH alone
The balanced chemical equation of propane is CH3CH2CH3.
Magnesium is a group 2 metal and Iodine is group 7 so MgI2 because Mg needs to loose 2 electrons to gain a full outer shell and Iodine only wants 1 electron so there needs to be 2 Iodine atoms.
Because each side of the equation shows two chlorine atoms, two sodium atoms, and two iodine atoms, and these are the only atoms present.
Its balanced equation is Ba2so4 + 2Nacl
No. The Alkali metals are Lithium, Sodium, Potassium, Rubidium, Cesium, and Francium. Fluorine, Chlorine and Iodine are Halogens.
2KI+MnO_2+3H_2 SO_4→2I+2KHSO_4+MnSO_4+2H_2 O
2NaI(aq)+Br2(l)-->2NaBr(aq)+I2(l) Sodium iodide+bromine-->sodium bromide+iodine
when an equation is balanced, both sides of the equation( products and reactants), equal the same amount.
The equation for balanced photosynthesis is: 6CO2 + 6H2O ------> C6H12O6 + 6O2
Balanced Equation 3Mg + N2---> Mg3N2
The balanced equation is 2HCl + K2O -> H2O + 2KCl.
Copper, Gold, Silver, Iodine, Rubidium, Indium. Have fun.
The 6M is irrelevant for this equation. Balanced Equation: Mg + 2HCl -> MgCl2 + H2
iodine sublimes to form I2
The balanced equation for the production of ammonia is the following: N2 + 3H2 ---> 2NH3
An equation must be balanced because of the law of conservation of matter.
Because H2O is the chemical formula of water and not a balanced equation.