Want this question answered?

Q: Calculate the centripetal force on the end of a 100 m (radius) wind turbine blade that is rotating at 0.5 revs. Assume the mass is 4 kg.?

Write your answer...

Submit

Still have questions?

Continue Learning about Physics

By radial force, we can assume you mean centripetal force Centripetal force = (Mass)(Radius)(Angular velocity)2

You question isn't very clear but I'll assume you are interested in the definitions of centripetal and centrifugal forces. Centripetal Force: Force on an object that pushes into a curved path Centrifugal Force: Force exerted by an object that is being forced to follow a curved path If you are on a merry-go-round holding onto a pole the pole exerts a centripetal forces on your hands that keeps you from flying off the edge. You exert a centrifugal force on the pole due to your mass and the acceleration you are undergoing due to your circular path. These forces are in equal and opposite directions as long as you hold on. If you let go both forces disappear and you travel in a straight line. However the pole you were holding travels in a curved path so from your perspective you are being flung off the ride. In Europe the units of force would be Newtons while anti metric zealots elsewhere might use slugs or pounds force. If you are referring to centripetal and centrifugal forces due to the earths rotation then the centripetal force is the portion of gravity acting on you that is needed to keep you from flying off into space due to your circular path on the surface of a rotating globe. The centrifugal force reduces the force you exert on the earth. It's equal to your weight on earth minus your weight on an equivalent sized earth that isn't rotating (you'd be a bit heavier in the later case). The magnitude of this effect in Europe wold depend on your exact latitude and altitude since these would determine your distance from the earth rotational axis and thus your rate of angular acceleration.

I assume you mean "uniform circular motion". That means that:* An object moves in a circle, and * The speed, and therefore also the angular speed, is constant. As an example, this occurs in many machines that have rotating parts.

I assume you're asking about a natural gas fired plant. The gas is burned to heat water and produce steam. The steam is piped to a steam turbine causing the turbine to spin rapidly. As the steam does work on the turbine, its temperature drops. The turbine is connected by a shaft to an electrical generator. The spinning generator converts this mechanical energy into electrical energy by moving magnets through conducting wires. This produces an electric field which pushes electrons through the wires.

If you assume that the initial speed is zero, you can calculate the distance using the formula:distance = 1/2 x acceleration x time squared

Related questions

By radial force, we can assume you mean centripetal force Centripetal force = (Mass)(Radius)(Angular velocity)2

I assume that your question is how you can use an engine to obtain electricity. If so, the idea is the following: You burn a fuel inside the combustion chamber of the engine. What this will do is to convert the chemical energy of the fuel molecules into thermal energy. You can then use some kind of rotor (turbine) that converts this thermal energy into mechanical energy by rotating the turbine. The mechanical energy is transmitted via an axle that connects the turbine to an electric generator. Simplifying, a generator comprises of a magnet that rotates inside a coil and electricity is then generated inside the coil of this generator via induction. That's how you obtain electricity from a combustion engine. I hope I understood your question correctly.

To calculate this speed, you need some more numbers, not just the distance from Earth to Sun. You need to know:* The gravitational constant * The distance from Earth to Sun * The mass of the Sun You DON'T need the mass of the Earth. Assume any mass; you can just call the mass of the Earth "m". Then calculate an expression for the gravitational attraction between Earth and Sun. Divide by the mass of the Earth, and you get a centripetal acceleration. Assuming a circular orbit for simplicity, the centripetal acceleration must be just this force. Use the formula for the centripetal acceleration along a circle (a = v squared / radius). (Don't forget to convert the distance from Earth to Sun, to meters!) Solve for "v".

Well, the turbine in a dam kills salmon and makes it almost impossible for them to try to get through. But if you're talking about windmill turbines, I have no idea. I'd assume that birds are smart enough to realize that they're dangerous, but I don't really know.

Assume the mountain is a cone. Now, go forth and calculate.

You question isn't very clear but I'll assume you are interested in the definitions of centripetal and centrifugal forces. Centripetal Force: Force on an object that pushes into a curved path Centrifugal Force: Force exerted by an object that is being forced to follow a curved path If you are on a merry-go-round holding onto a pole the pole exerts a centripetal forces on your hands that keeps you from flying off the edge. You exert a centrifugal force on the pole due to your mass and the acceleration you are undergoing due to your circular path. These forces are in equal and opposite directions as long as you hold on. If you let go both forces disappear and you travel in a straight line. However the pole you were holding travels in a curved path so from your perspective you are being flung off the ride. In Europe the units of force would be Newtons while anti metric zealots elsewhere might use slugs or pounds force. If you are referring to centripetal and centrifugal forces due to the earths rotation then the centripetal force is the portion of gravity acting on you that is needed to keep you from flying off into space due to your circular path on the surface of a rotating globe. The centrifugal force reduces the force you exert on the earth. It's equal to your weight on earth minus your weight on an equivalent sized earth that isn't rotating (you'd be a bit heavier in the later case). The magnitude of this effect in Europe wold depend on your exact latitude and altitude since these would determine your distance from the earth rotational axis and thus your rate of angular acceleration.

Assume you have the growth rates for each month, then you: ....

When we view the rising and setting of the sun, we assume the viewpoint of a motionless Earth, but we know that the Earth is actually rotating on its axis, and the sun does not orbit the Earth.

Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.

The previous answer supplied was wrong. First, let us clarify the question. 1. We are going to assume we have an axially symmetric object rotating about its axis of symmetry. 2. The object has uniform density. 3. Stress at any one point is radial only and only due to the mass along the same radial line. 4. Gravity is not part of this. The problem then is equivalent to a chain rotating with one end tied to a fixed axis and its length extending perpendicular to the axis of rotation. The force experienced by any link in the chain is due to the sum of the centripetal forces of all links further out. Thus the closest link, or the link on the axis of rotation, feels the greatest stress. So, the previous answer was correct in identifying the location but incorrect in the reasoning.

If you assume a rectangular building, you measure the length and the width (in feet, in this case), and multiply.

They usually just measure current used and assume a known voltage.