4.4 moles CO2 x 6.02x10^23 molecules/mole = 2.65x10^24 molecules of CO2

1 mole of CO2 is 40.016 grams. 2.86 grams of CO2 is, therefore, 0.07147 moles, which is 4.304 x 1022 molecules.

For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams33.0 grams C / (44.0 grams) = .750 moles CO2

You must use the Ideal Gas Law to calculate the number of moles of CO2 and then convert the number of moles of CO2 to a mass in grams. Here it is: PV=nRT @STP, P = 1atm, T= 273K, R = .08206 L atm K-1 mol-1 1(1.6)=n(.08206)(273) 1.6=22.4n n=14 moles CO2. 14 moles CO2 x 44.01grams/1 mole CO2 =620 grams CO2(considering significant figures).

number of moles of co2 is 5.6 lit at ntp According to the relation that PV=nRT 760*v=5.6*0.0821*273 V=0.1649

0.75 moles CO2 x 6.02x10^23 molecules/mole = 4.5x10^23 molecules

The 3 is a coefficient. It is the number of molecules, or the number of moles.

For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2=44.0 grams3.07 moles CO2 Ã— (44.0 grams) = 135 grams CO2

For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams454 grams CO2 / (44.0 grams) = 10.3 moles CO2

# Moles CO2 * 44.01 g CO2 / 1 Mole CO2 = # g CO2

For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2= 44.0 grams1.50 moles CO2 Ãƒâ€” (44.0 grams) = 66.0 grams CO2

To convert molecules to moles you have to divide the molecules(particles) by Avogadros Number(6.02x10^23). ex:how many moles of CO2 in 3.9x10^22 molecules? 3.9x10^22/6.02x10^23=6.47 moles of CO2

calculate the number of moles of carbon and of the other and by number of moles you can proceed further. the next step is that you divide by the smallest ratio. hence obtaining your empirical formula.

For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2=44.0 grams2.00 moles CO2 Ãƒâ€” (44.0 grams) = 88.0 grams CO2

CO2 + 4H2 --> CH4 + 2H2O0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH40.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O-------------------------------------------------------------------------------------add= 1.50 moles total product====================

5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2

44.8 liters in 2 moles of CO2

Two moles of CO2 have a mass of 88.01g.

4,54 L of CO2 have 0,204 moles.

The mass of 2 moles of CO2 is 88,02 g.

You first have to find how many moles of CO2 you have so you find its molar mass, (Carbon=12 Oxygen = 16(2)) then you add 12+32 to get the molar mass which is 44 you should also be given a mass, of how much CO2 there is.. or else you cannot calculate the moles. moles are mass/molar mass once you get the moles just multiply the number of moles by Avogadros constant (6.02x1023) Say if the mass was 4.56 g of C02 that you had then you just do 4.56/44 = 0.103636363 mol now multiply that by avogadro's constant and you have the number of atoms/particles/formula units

The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.

The number of molecules is 7,52767607125.10e23.

The number of molecules is 0,90332112855.10e23.

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