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Factoring and Multiples

Can 3 always be divisible by 9 but divisible by 6?

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2012-03-01 14:10:16
2012-03-01 14:10:16

Multiples of 9 and 6 are also divisible by three, the reverse is not true.

15 is divisible by 3, but not 6 or 9.

27 is divisible by 3 and 9, but not 6.

12 is divisible by 3 and 6, but not 9.

54 is divisible by 3, 6 and 9.

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Related Questions


No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6


72,344 is not evenly divisible by 3 or by 6 or by 9.


All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.


42 is divisible by 2, 3 and 6 but not by 9.


1350 is divisible by all of the numbers of 3, 6 and 9


All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.


The smallest number divisible by 3 6 and 9 is 18.


Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.


Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.


yes. 2 + 1 + 6 = 9 9 is divisible by 3 so 216 is divisible by 3.


Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.


No, because when something is divisible by 6, it is divisible by 2 or 3. This is divisible by 3, but not 2.



1, 2, 7, 3 and 6 are not divisible by 4 and/or 9. 12736 is divisible by 4 but not by 9.


Not always because 33 is divisible by 3 but not by 9


not divisible by 9.but it is divisible by 4.


It is divisible by 2, 3, 4, 6 and 9.


No. For example, 9 is divisible by 3 and 9, but not 6. Even numbers that are divisble by 3 and 9 are also divisble by 6.


To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.


No. 1+9+6=16, which is not divisible by 3; 1+4+6=11, which isn't divisible by 3 either. No. 1+9+6=16, which is not divisible by 3; 1+4+6=11, which isn't divisible by 3 either.


9 is greater than 6 and divisible by 3.


434 is evenly divisible by 2.It is not evenly divisible by 3, 6, or 9.


3 and 5, yes. 6 and 9, no.


72,344 is evenly divisible by 2, but not by 3, 6, 9, 5, or 10.


Your numbers appear to be mixed up because 20007 is divisible by 3 and 9 but not by 6 which is not one of its factors



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