This is not possible because a 120v switch disconnects one conductor while a 240v application requires that both hot conductors be disconnected simultaneously. The proper solution is to use a double pole 240v switch of the correct size. It must have contacts which are rated to carry the appliance's starting and running currents (amps). A switch with under-sized contacts would be likely to get very warm - or even overheat - to such an extent that it might become a dangerous fire hazard. IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS.
If you do this work yourself, always turn off the power
at the breaker box/fuse panel BEFORE you attempt to do any work
AND
always use a meter or voltage indicator
to insure the circuit is, in fact, de-energized.
Yes if you have a step up transformer. Primary voltage 120 volts, secondary output voltage 240 volts.
Yes, the rating of 250 volts on the switch is the maximum voltage that can be applied to the switch.
The equation you are looking for is Amps = Watts/Volts. To change kW to watts, multiply kW x 1000.
5 amps
yes 240volts is 240 volts
Pwer is volts times amperes. 120 volts times 10 amperes = 1.2 KW
The maximum is 15 x 120 watts, 1800 watts.
power supply
Your neutral May not be grounded good
32 volts of course. But the real difference is the way the power company has "tapped" their supply step down transformers.
120volt
Yes.
Check the back of the charger, if it says "100-240volts" than yes.
1 d0nt kn0w but have fun
The equation you are looking for is Amps = Watts/Volts. To change kW to watts, multiply kW x 1000.
yes
5 amps
Supply voltages are simply 'nominal', or 'named' voltages, and they are allowed to vary in value within statutory limits. In the UK, for example, the nominal supply voltage is 230 V but is allowed to vary within the range +10% to -6%. 240 V is well within this range and, so, yes, there is absolutely nothing wrong with using a 240-V load with a 230- V supply or vice versa.
Work it out for yourself. The equation is: Z = E/I, where Z is the impedance, E is the supply voltage, and I is the load current.