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Can a batsman take more than 6 runs by running?

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Thad Mitchell

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Q: Can a batsman take more than 6 runs by running?
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Batsman 1 hits the 1st ball behind the keeper and the ball hits bat pad fielder helmet which is behind the keeper, so batsman 1 gets 5 runs and in the next ball batsman 1 scored another one run. So batsman 1 reached 100 runs and he crossed the pitch. Now 1 ball, 1 run to win and batsman 2 is about to strike. He hits the amazing six which makes him score the century and also team won the match. So in 3 balls both the batsman scored their century without fall of wicket. I hope above is the right answer. Thank u Regards, Karthick Batsman 1 hits the 1st ball to 4 runs in the next ball batsman 1 scored 3 runs but umpire declares one run short now batsman 1 complete his century and batsman 2 is on strike and team needs one run to win Now 1 ball, 1 run to win and batsman 2 is about to strike. He hits the amazing six which makes him score the century and also team won the match. Regards, Sanjit


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Two batsmans each on 94 7 runs required to win in 3 balls both make unbeaten 100 how?

1st Ball : First Batsman Hit a Dil-Scoop to a Wicket Keepers Helmet on the Field. then get 5 runs for it. 2nd Ball : First Bats Man get a 1 run then he reaches 100. 3rd Ball : 2nd Batsman Hit a six Both Scored 100 and match win ==================================================== 1st BALL : ONE BATSMAN HIT A FOUR. 2nd Ball : same batsman make a shot and take three runs but onje run is short and it will be counted as 2 runs. 3rd Ball : the other batsman hit a SIX and won the match. Both are at unbeaten 100. Also the case is the overs might be reduced to 48.2 overs or 48.1 overs something then both batsman can hit a SIX http://www.orkut.co.in/Profile.aspx?uid=14944937969814434926 Ball1:Batsman1(94) hit six , completes his 100 and retired hurt because of injury. Two balls and One run to win. Ball2:New Batsman(0) tries to take single and run out. Batsman2(94) at the striker end and non striker end got replaced by the retired hurt batsman. One ball and One run to win. Ball3:Batsman2(94) hit six and completes his 100. Both unbeaten at 100 and Match Won. Note: It's mentioned that in case the ball hits the keeper's helmet the ball maybe called a dead ball. Not sure on this one but even if it is called a dead ball still this answer holds true.


Two batsman on 94 runs 2balls remaining and 7runs to win both the batsman made their century and won the match?

OK, I can only see one possible way this could happen: - First ball, Batsman A on strike (94*), 7 to win - the ball is struck (presumably to somewhere in the outfield) and the batsmen take three runs. However, on one of the runs, one of the batsmen accidentally fails to make his ground, so the umpire calls a short run and that run is disallowed (as per Law 18.4(a)). While the ball is still in play the fielder throws it to the wicket-keeper but overthrows it, and the ball goes to the boundary and so an additional four runs are awarded (as per Law 19.6). Thus, six runs (3 runs - 1 short run + 4 overthrows) are awarded to Batsman A for his century and according to Law 18.12(a), Batsman B would now be on strike. - Second ball, Batsman B on strike (94*), 1 to win - the ball is struck over the boundary for six. Batsman B scores his century and his team wins the match. If anyone knows of any other way this can be done, please let me know as I would be very interested to hear your solutions. However, according to the laws of cricket, that is definitely one way to solve the problem. PS - Just thought I'd correct some of the other suggestions. If the ball hits a helmet on the field, the batting side is awarded five penalty runs which would be added to the scorecard as Extras and not the batsman's score. If the last two balls of the innings were in different overs then Duckworth/Lewis would have to be applied and the target would almost certainly change. Any no-balls would again be added as Extras and would then make it impossible for both batsmen to score centuries.


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