Yes. Acceleration is independent of speed. A perfect example of an object with zero speed but nonzero acceleration is an object at the apex of being thrown upward. The entire time it is in the air it is accelerating downward. At its maximum height its speed is zero.
If you are moving at a speed of ceratin speed and there is no force trying to slow you down, and there is no force trying to speed you up. Then there is zero acceleration. An example would be : an object in out in space, if you throw a object away from you the object will float away, since there is no force working on the object after you throw it the object is moving away in a locked speed from you, but have zero acceleration because there is no force affecting the object
Yes, just as the acceleration is reversing your direction of movement.
An object with an increasing speed is in fact accelerating, hence the acceleration vector may be continually changing (but >0) with time.
-- acceleration = 0 -- velocity (speed and direction) exactly equal to the observer's velocity
If speed is constant, acceleration is zero. Anything multiplied by zero equals zero. F = m * a, where F is force, m is mass and a is acceleration. F = m * 0 = 0
An object moving at a constant speed in a straight line has an acceleration of 0. An object at rest also has an acceleration of 0. So, the two things I see in common are their accelerations, which are both 0.
0 velocity 0 acceleration The forces on the object are balanced: it is in equilibrium. (The forces are balanced on any object with 0 acceleration, even if it is moving.)
If an object is sustaining a constant velocity it has 0 acceleration, because acceleration is either increasing or decreasing speed.
If you are moving at a speed of ceratin speed and there is no force trying to slow you down, and there is no force trying to speed you up. Then there is zero acceleration. An example would be : an object in out in space, if you throw a object away from you the object will float away, since there is no force working on the object after you throw it the object is moving away in a locked speed from you, but have zero acceleration because there is no force affecting the object
Yes, just as the acceleration is reversing your direction of movement.
An object with an increasing speed is in fact accelerating, hence the acceleration vector may be continually changing (but >0) with time.
v^2 = v0^2 +2a*height v = speed v0 = starting speed (0 in this case) a = acceleration (9.8 is the acceleration of gravity) the speed of the object won't change based on the mass
-- acceleration = 0 -- velocity (speed and direction) exactly equal to the observer's velocity
If speed is constant, acceleration is zero. Anything multiplied by zero equals zero. F = m * a, where F is force, m is mass and a is acceleration. F = m * 0 = 0
Answer This occurs when an object istraveling in one direction but has an acceleration in the opposite direction, which means it is decreasing in speed. For a given period of time, the speed has decreased. Acceleration is the change of velocity per second. T1 = 5 seconds V1 = 100mph T2 = 10 seconds V2= 50 mph Acceleration = (V2 - V1 ) / (T2 - T1) = (50-100)/(10-5) = -10 ft/sec/sec Positive(+) acceleration means an object will be going faster over an interval of time.
Falling object acceleration is due to gravity, and is therefore a constant. However, because there is a magnitude to this acceleration, the falling object will continue to increase in speed until it reaches its terminal velocity. We can also observe this quantitatively. Imagine that we have an object falling from a cliff. At initial, the velocity is 0, acceleration is -10 m/s^2(rounded for simplicity). After one second, we can calculate the velocity. V= V(o) + a(t) V = 0 +(-10)(1) -10 m/s. The speed is just the magnitude of the velocity, or + 10 m/s. To prove that it will increase even more in speed (even though it already from from 0 m/s speed to 10 m/s speed with negative acceleration), here's another example to further the point which expands on the problem already given. Let's evaluate speed at 2 seconds. V= V(o) + a(t) V= 0 + (-10)(2) V= -20 m/s. so speed = +20 m/s Hopefully you can see now that while velocity is decreasing, the magnitude of it, speed, is increasing, and that a falling object always has negative acceleration of about -10m/s^2.
If the speed is constant at 50 mph, then the acceleration is 0.