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  • No, you cannot catch STD from kissing your grandmother.
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Q: Can you get an STD from kissing your grandmother?
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Her grandmother, "Nanny".


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#include<iostream> int main() { std::cout << "sin(1) = " << std::sin(1.0) << std::endl; std::cout << "cos(1) = " << std::cos(1.0) << std::endl; std::cout << "tan(1) = " << std::tan(1.0) << std::endl; std::cout << "asin(1) = " << std::asin(1.0) << std::endl; std::cout << "acos(1) = " << std::acos(1.0) << std::endl; std::cout << "atan(1) = " << std::atan(1.0) << std::endl; } Output: sin(1) = 0.841471 cos(1) = 0.540302 tan(1) = 1.55741 asin(1) = 1.5708 acos(1) = 0 atan(1) = 0.785398


How do you split a string in delimit c plus plus?

#include<iostream> #include<vector> #include<string> std::vector<std::string> parse (const std::string& s, const char delim) { std::vector<std::string> result {}; auto start = 0U; auto end = s.find (delim); while (end != s.npos) { result.push_back (s.substr(start, end - start)); start = ++end; end = s.find (delim, start); } result.push_back (s.substr (start, s.npos - start)); return result; } std::vector<std::string> parse (const std::string& s, const std::string& delim) { std::vector<std::string> result {}; auto start = 0U; auto end = s.find (delim); while (end != s.npos) { result.push_back (s.substr(start, end - start)); start = end + delim.length(); end = s.find (delim, start); } result.push_back (s.substr (start, s.npos - start)); return result; } int main() { std::string str1 = "This is a string that will be parsed by a single-space delimiter."; std::string str2 = "This==is==a==string==that==will==be==parsed==by==equal==operator."; std::string str3 = "This string has no delimiter."; std::cout << str1 << std::endl; std::vector<std::string> v1 = parse (str1, ' '); for (auto i : v1 ) std::cout << i << std::endl; std::cout << std::endl; std::cout << str2 << std::endl; std::vector<std::string> v2 = parse (str2, "=="); for (auto i : v2 ) std::cout << i << std::endl; std::cout << std::endl; std::cout << str3 << std::endl; std::vector<std::string> v3 = parse (str3, '\\'); for (auto i : v3 ) std::cout << i << std::endl; std::cout << std::endl; }