1. Put the mixture in water and stir.
2. AgCl is not soluble, NaCl is soluble.
3. After filtering NaCl passes in solution and AgCl remain on the filter.
For example another salt: NaCl + AgNO3 = AgCl + NaNO3
No, the dilute solutions of highly water soluble compounds are unsaturatd as solution of NaCl but dilute solution of AgCl or BaSO4 are saturated because they are very little soluble in water.
To determine the mass of silver chloride produced, we need to know the balanced chemical equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) that produces silver chloride (AgCl) as a precipitate. Once we have the balanced equation, we can use the stoichiometry of the reaction to determine the number of moles of AgCl produced, and then convert that to mass using the molar mass of AgCl.
This is called a double replacement reaction. An example might be something like this ...NaCl(aq) + AgNO3(aq) ---> NaNO3(aq) + AgCl(s)
Not necessarily. Some reactions do have the same number of moles, and some do not.Examples: NaCl + AgNO3 ==> NaNO3 + AgCl same # of moles N2 + 3H2 ==> 2NH3 different # of moles
(AgCl has Ksp = 1.8 x 10-10)-5.1 x 10-10
The reaction is: NaCl + AgNO3 = NaNO3 + AgCl Silver chloride is a white precipitate.
when sodium chloride and silver nitrate reacts then we get silver chloride and sodium nitrate.
The reaction is:AgNO3 + NaCl = AgCl(s) + NaNO3
When sodium chloride and silver nitrate are mixed, a metathesis reaction takes place. The silver ion becomes bonded to the chloride ion. Since silver chloride is insoluble, this substance precipitates out of solution.
When silver nitrate (AgNO3) is mixed with sodium chloride (NaCl), a white precipitate of silver chloride (AgCl) is formed. This reaction is a double displacement reaction where the silver cation from AgNO3 and the chloride anion from NaCl switch partners to form the insoluble AgCl precipitate.
One mole of AgNO3 reacts with one mole of NaCl to form one mole of AgCl precipitate. Therefore, 0.100 mol of AgNO3 will form 0.100 mol of AgCl precipitate when reacted with excess NaCl.
AgNO3(aq) + NaCl(aq) --> AgCl(s) + NaNO3(aq)
NaCl(aq) + AgNO3(aq) = AgCl(s) + NaNO3(aq) - so the precipitate is white silver chloride.
AgCl and NaCl respectively.
The chemical equation for combining silver nitrate (AgNO3) and salt water (NaCl) is: AgNO3 + NaCl -> AgCl + NaNO3. This reaction forms silver chloride (AgCl) and sodium nitrate (NaNO3), which are both soluble in water.
trick question guys, there is none. this question should be deleted for such stupidity. FOOCK CHEMISTRY!