Top Answer

No.

There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.

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04y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2

2y = 4x + 4y = 2x + 2

3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2

y + y + 2 = 182y + 2 = 182y = 16y = 8whew !

No 2y-3 is not equals y plus 2AND how old are u?

6x+2y=4 gives y=2-(1/3)x

Subtract by 7x and divide by 2.

2y(x+2)=

2y = 4 (divide both sides by 2 to solve) y = 2

4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80

Your answers are x = 2 & y = 1Original Equationsx - 2y = 03x + 2y = 8Solve for a variable (x)x = 2ySubstitute x with its equation3*(2y) + 2y = 86y + 2y = 88y = 8y = 1Solve for second variablex = 2*(1)x = 2Check your answer(2) - 2*(1) = 03*(2) + 2*(1) = 8

2y = 15 y = 15/2 y = 7.5

you cannot solve this without more information. When 3 variables are involved, you need 2 equations to solve for the answers for both variables.

2y+26 = 28 2y = 28-26 2y = 2 y = 1

Exactly (2y + 4) .

2y - 9x = 14 2y = 14 + 9x y = (14 + 9x) / 2

If: -4x+2y = 9 Then: 2y = 4x+9 Divide all terms by 2: y = 2x+4.5 which is now in slope intercept form

For 5x+y=1, you would subtract 5x from each side, so you would get y=1-5x For 3x+2y=2, you would subtract 3x from each side, and then divide by 2. 2y=2-3x y=1-(3/2)x

5y-2y= 3y+2 5y-2y-3y= 2 0y= 2

√(2y) + 3 = 11 √(2y) = 11 - 3 = 8 √2 x √y = 8 √y = 8/√2 y = (8/√2)2 = 64/2 = 32

If the two equations are (i) 4x + 2y = 12 and (ii) x + 2y = 6, proceed as follows: Rewrite (ii) as x = 6 - 2y; substitute this expression for x into (i) to result in 4(6 - 2y) + 2y = 12, or 24 - 8 y + 2y = 12, or - 6 y = 12 -24 = -12, or y = -12/-6 = 2. Then, back to (ii) again, x = 6 - 2(2) = 2.

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