Yes no matter what the accident you can sue them 30 years later if you feel like it As long as you haven't already sued them
Sue is 10. Leah is 16 John is 15 Making the combined ages 41.
8
use an equation x=sue x+x+6+x+11=41 -17 -17 3x= 24 /3 /3 x= 8 sue is 8
If Jim is 'x' years old then Nate is x+6 and Sue is x+2. So (x+6)+(x+2)+x=34. Then 3x + 8 = 34 leads to 3x = 26 so x = 8 and 2/3. Sue is 2 years older so she is 10 and 2/3 years old or 10 years and 8 months old.
30 duhh!your a idiot...... its 8
Sue is 8 years old. Sue (8) + Leah (14) + John (19) = 41 Solve algebraically by stating all ages in terms of Leah's (L) Sue S = L - 6 (Leah = Sue + 6) John J = L + 5 (Leah = John + 8) S + J + L = 41 (L-6) + (L+5) + L = 41 3L -1 = 41 3L = 42 L = 14 S = 8 J = 19
Ok, this is funny. Let's change the "circumstances" a bit. If a person was convicted of murder, do you feel that the convicted could sue the homicide detectives who took 6 years to nail him? You lack serious reasoning.
use this website. they may be anle to answer your question.www.freelawanswer.com/law/350-law-6.html
The sum of the three kids ages is 41. So we can say that S+J+L=41 We know that Leah is years older than Sue. So we can write her age as L=S+6. We also know that John is 5 years older than Leah. So we can write his age as J=L+5 Since L=S+6 we can write J as S+6+5 or J=S+11 Now we have all three kids ages as terms of Sue's age. S S+6 S+11 Now we add those together and set them equal to 41. 3S+17=41 3S=24 S=8 Sue is 8 years old.
According to http://www.senioryears.com/soapbox29.html the answer to how long an accident stays on record is approximately 6(six) years. An accident is "chargeable" for 3 years after the accident. Some insurance companies will also underwrite, but not charge, for accidents for 5 or 6 years. As far as staying on your "record", the CLUE (Comprehensive Loss Underwriting Exchange) report will show claims activity of any sort for up to 10 years.
Senate is 6 years and the House is 2 years.
6 years