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First find the area of the frame and photo combined; then find the area of the photo alone. Then find the difference. Since we know that the diameter of the photo is 8, its radius must be 4, and the area of the photo is πr2 = π42 = 16π. We are given that the frame is 2 inches wide, so we can say that the radius of the frame and photo combined is 4 + 2 = 6. So the area of the frame and photo combined must be π62 = 36π. Finally, to get the area of only the frame, we subtract the area of the photo from the area of the frame and photo combined, giving us 36π - 16π = 20π.

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Q: Circular frame with a width of 2 inches surrounds a circular photo with a diameter of 8 inches Assuming that area of the frame does not overlap the area of the photo what is the area of the frame?
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