A capacitor that is suddenly connected to a battery will charge to the battery voltage. The time to do this is dependent on the current capacity of the battery and wiring, and the capacitance of the capacitor. This represents an instantaneous short circuit, which lasts for a (usually) very short time - but damage could be done if there was no resistance.
A charged capacitor that is suddenly disconnected from a battery will hold that voltage. The length of time it will hold is dependent on how much leakage current there is.
Probably vacuum ac capacitors.
http://www.allaboutcircuits.com/vol_1/chpt_16/2.html just read it once every thing will b clrd in your mind
Gain in a CE configuration of a BJT is collector resistance divided by emitter resistance, subject to the limit of hFe. The emitter bypass capacitor will have lower impedance at high frequency, so the gain will be higher at higher frequency, making this a high-pass amplifier.
All amplifier typically exhibit a band-pass frequency response. The cut off frequency in the low end is usually determined by the coupling band bypass capacitor .and the high frequency limit is typically determined by internal capacitances in the transistor itself.
You can use a larger capacitor (more uF) in the decoupling or smoothing parts of the circuit, but not in anything that is used to control the frequency response, but that is unlikely.
That depends on the value of the capacitor and other components in the circuit.
If a resistor is connected in series with the capacitor forming an RC circuit, the capacitor will charge up gradually through the resistor until the voltage across the capacitor reaches that of the supply voltage. The time called the transient response, required for this to occur is equivalent to about5 time constantsor5T. This transient response timeT, is measured in terms ofτ= R x C, in seconds, whereRis the value of the resistor in ohms andCis the value of the capacitor in Farads. This then forms the basis of an RC charging circuit were5Tcan also be thought of as"5 x RC".
Try adding a adding a capacitor.
Pin 8 is called Strobe pin. It is used for Phase compensation and Gain control to optimize frequency response. For this a capacitor(usually 47 pF) is connected between pin 8 and pin1
Because the response characteristic of a capacitor is time dependent - it's impedance changes as a function of time. Differentiating will show the speed of this change, just like differentiating a line will give the slope of the line.
Probably vacuum ac capacitors.
R for resistor, C for capacitor. RC circuit is a circuit built with a resistor and a capacitor. This circuit will have a typical pulse response that looks like exponential decaying and a typical resonance frequency.
Theoretically, forever, because as the voltage on the capacitor approaches the source voltage, the available current to charge the capacitor approaches zero.In practice, however, it simply depends on what you call "charged".In the simple example of a capacitor being charged from a voltage source in series with a resistance, the voltage is given by ...VT = Vs (1 - e -T/RC)... so, if your definition of "charged" is 99% of VT then T would have to be 5 RC's or 5 time constants.If a resistor is connected in series with the capacitor forming an RC circuit, the capacitor will charge up gradually through the resistor until the voltage across the capacitor reaches that of the supply voltage. The time called the transient response, required for this to occur is equivalent to about5 time constantsor5T. This transient response timeT, is measured in terms ofτ= R x C, in seconds, whereRis the value of the resistor in ohms andCis the value of the capacitor in Farads. This then forms the basis of an RC charging circuit were5Tcan also be thought of as"5 x RC".
it is brutal
A conversation-stopper, or a show-stopper.
http://www.allaboutcircuits.com/vol_1/chpt_16/2.html just read it once every thing will b clrd in your mind
Stendhal syndrome