C2H4O2=molecular formula, basically you multiply the empirical formula by 2.
Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
ch2o and c6h12o6
C6h12o3
High resolution mass spectrometry weight. It is used to narrow down the molecular formula of an unknown molecule.
That is a molecular formula.I can't off the top of my head think of any compound with that molecular formula, though. It's not methoxyethane or a propanol, because it's got one too few hydrogen atoms. It's not propanone or cyclopropanol or oxetane or a propenol, because it's got one too many hydrogen atoms.
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
ch2o and c6h12o6
In a laboratory the mysterious compound is initially weighted and then will undergo reactions to be broken down into its constitutes. The individual elements or other compounds will be determined and then be weighed. Using information known on those elements and compounds, scientist will be able to discover the molar mass for each of them. Using the equation n = m/ M (mols = mass over (divided by) molar mass) they are able to determine the moles for each of the elements/compound. the unknown compound will be determined by the product with the lowest number of moles (closest to zero) have its number dividing all the other products (see it as for each mole of that element/compound there will be a requirement of N amount of moles from the other product(s)). This result will give the ratios for the constitutes in the unknown compound (the subscripts). This formula here will be the empirical formula (which may not be the actually formula for the reaction, it is the simplest ratio). Let the unknown compound be X. A and B are the resulting constitutes of X. After determining the correct mols of A and B where B moles is closest to 0, we divide Amols by Bmols and the resulting number is near a whole number. This number will be the subscript for A and will determine the empirical formula of X. If Bmols = 1 and Amols = 2 the unknown compound will have the empirical formula of A2B.
There is no easy answer to this question. First, it depends what information you have to start with. Do you have the name? Do you know what elements are found in the substance?If you are given the name of the molecule, you can often find the molecular structure of that compound by simply using the Google search engine online and searching for the name. It is often give you the answer! There are certain compounds that you should be familiar with also. Also, there is a set of official rules that determine the name of a specific compound, so that if you have the formula, you can name it correctly, and if you have the name, you can determine the formula. Unfortunately, many chemicals also have common names that do not follow these rules, and you just have to memorize those, or look them up with Google.See the Related Questions and Web Links to the left for some information about how compounds are named and how to go from a formula to a name and vice versa.
C6h12o3
C6h12o3
calculate the number of moles of carbon and of the other and by number of moles you can proceed further. the next step is that you divide by the smallest ratio. hence obtaining your empirical formula.
This formula is for magnesium chloride hexahydrate: MgCl2.6H2O.
Probable the boiling point elevation.
High resolution mass spectrometry weight. It is used to narrow down the molecular formula of an unknown molecule.
That is a molecular formula.I can't off the top of my head think of any compound with that molecular formula, though. It's not methoxyethane or a propanol, because it's got one too few hydrogen atoms. It's not propanone or cyclopropanol or oxetane or a propenol, because it's got one too many hydrogen atoms.