Elements and Compounds
Salt (Sodium Chloride)

Did NaCl require a transport protein for diffusion?


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Answered 2010-02-21 03:24:33

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It does require a transport protein as it disassociates into charged ions and it is not lipid soluble. Only lipid soluble molecules diffuse freely through living membranes.

diffusion coefficient nacl in water at difrent concentration

nacl diffuse in plasma membrane because there are protein channels that allows certain ions to diffuse around the membrane, like sodium and chloride ions, please note that these channel proteins are selectively permeable meaning sodium channels only allow sodium to enter the cell and so on... urea diffuses into the pm the same way through facilitated diffusion of certain protein channels glucose diffuse into the pm as a part of secondary active transport, which means it uses ATP indirectly. it diffuses in the process called symport

Salt (NaCl) is an inorganic compound.

No, not really. Diffusion works when molecules move from an area of higher concentration to an area of lower concentration. They move independently of one another. So even if you have a high level of NaCl, the glucose concentration will diffuse in the same manner.

5% NaCl solution is unusually high. And because all living organisms seek to maintain an isotonic balance with their environment,osmotic diffusion will occur in order to re-establish this balance.Hence,there will be a diffusion down the gradient i.e. from the medium containing the NaCl solution,into the bacterial cell which has solutes dissolved in it but insufficient to even out this balance.The end result will then be lysis or bursting of the bacterial cell,as it gorges in the NaCl to maintain equilibrium.

In solution, NaCl can split into Na+ and Cl- ions. These ions are indeed needed to stabilise the hydrophilic residues of the protein molecule that are exposed on the surface. So NaCl is a stabilising agent in various protocols even in the extraction, but it does not has any role in lysing the cells or neutralising other biomolecules.

Beef extract for carbohydrates Peptone for protein and NaCl as salt

To get 0.15 moles of NaCl, mass of NaCl = moles * molar mass = 0.15 * (23+35.5) = 8.775 g and 0.15M is 0.15 mole of NaCl in on liter solvent which equals 8.775 g then ypu add solvent up to 1 liter.

Transport number of Na+ ion in infinitely diluted solution (transport number of sodium ion in pure wate) is about 0.40, on the other hand transport number of K+ ion is 0.49.Thus, during the long time of operation NaCl causes the imbalance of ions in the electrochemical cell.Fortunately, By using the KCl ssalt bridge this critical problem can be solved.Therefore, use of NaCl in salt bridge is forbidden...

Rains and rivers dissolve salt from salt deposits and transport NaCl in seas or lakes.

Almost exactly 1 M - to be exactly 1.0M would require 58.5 g NaCl

If there is 99.1% water (0.9% NaCl) inside the cell and 99.5% water (0.5% NaCl) outside the cell, the water goes from where it is highest (99.1) to where it is lowest (99.5). This is the concept of osmosis, or the diffusion of water across a semi-permeable membrane. Diffusion always occurs from a high to a lowconcentration of molecules as they are moving due to their kinetic energy (energy of motion).

1 mole NaCl = 58.44g NaCl0.48mol NaCl x 58.44g NaCl/1mol NaCl = 28g NaCl

1 mole NaCl = 58.443g NaCl 234g NaCl x 1mol NaCl/58.443g NaCl = 4.00 moles NaCl

An antigen has to be a protein or molecule of a certain and complex size. NaCl, table salt, is not large enough of a molecule to be an antigen.

1 mole NaCl = 58.442g NaCl (the atomic weight of Na and Cl in grams) 13g NaCl x (1mol NaCl/58.442g NaCl) = 0.22mol NaCl

Take 43.8g NaCl divided by the molar mass of NaCl which is 58.443g and then you get your moles of NaCl. 43.8/58.443=0.749 moles NaCl

I'm going to assume that you mean 23.34g of NaCl. 1 mole NaCl = 58.442g NaCl (the atomic weight of Na and Cl in grams) 23.34g NaCl x (1mol NaCl/58.442g NaCl) = 0.3994mol NaCl

1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl 3.6g NaCl x 1mol NaCl/58.443g NaCl x 6.022 x 1023 formula units NaCl/mol NaCl = 3.7 x 1022 formula units NaCl

1 mole of NaCl is 58.44 g 200 g NaCl * (1 mol NaCl/58.44 g NaCl) = 3.422 mol NaCl There are about 3.4 moles in 200 grams of NaCl.

The dissociation of NaCl is: NaCl-------------Na+ + Cl-

1 mole NaCl = 58.44g 0.1601mol NaCl x 58.44g NaCl/mol NaCl = 9.35g NaCl

NaCl is already balanced. Na+ and Cl- make NaCl.

NaCl is an ionic compound. NaCl is sodium chloride.

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