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Yes they do for a triangle using Pythagorean theorem 5 squared + 12 squared = 13 squared

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6y ago
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6y ago

Sides of lengths 5, 12 and 13 do not form a right angle, but a right angled triangle.

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6y ago

Yes.

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Q: Do 5 12 13 form a right angled triangle?
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Can a triangle be drawn with 15 12 9?

A triangle with the above dimensions would be a right angled triangle.


Is 7 8 12 a right triangle?

7, 8 & 12 are the sides of the triangle.And, for a right angled triangle the Pythagoras theorem is always applicable!Pythagoras theorem states that for a right angled triangle:(Longest Side)2 = (Side-1)2 + (Side-2)2(Longest side is called as the hypotenuse).So, using data in the question:If its a right angled triangle--->122 = 72 + 82i.e. 144 = 49 + 64 => 144 = 113, which is clearly not true!Hence, the triangle with the given sides is not a right triangle.


What kind of triangle is one with side lengths of 5 12 and 13?

A right-angled triangle. Per Pythagoras: (5*5) + (12*12) = 13*13


Is A triangle with sides of lengths 12 15 and 20 a right triangle?

No. Pythagoras' theorem states that when the square of the hypotenuse is equal to the sum of the squares of the other two sides then it is a right-angled triangle. The hypotenuse is the longest side (opposite the supposed right angle). In this case the hypotenuse is 20. The square of 20 is 400. The other two sides are 12 and 15. The square of 12 is 144 and the square of 15 is 225. The sum is therefore 225 + 144 = 369, which is not equal to 400, therefore the triangle cannot be a right-angled triangle.


Could measurements 5 12 13 be a right triangle?

yes.the property of right angled triangle is that the square of the hypotenuse is equal to the sum of other two sides thus (5*5)+(12*12)=169=(13*13)


What is the area of a right angled triangle with a base of 12km and a height of 35km?

1/2*12*35 = 210 km2


What is the length of the longest side of a right angled triangle if the two shorter side are 5cm and 12 cm?

13 cm


Can 5 12 and 13 form a right triangle?

yes.


Can the numbers 7 9 and 12 be the lengths of the sides of a right triangle?

if it makes a right angled triangle then c squared = a squared + b squared 12^2 = 7^2 + 9^2 144 = 49 + 81 but 144 doesn't equal 130 so no it doesn't make a right angle triangle


Does 51213 form a right angle?

If you mean 5 by 12 by 13 then they will form a right angle triangle


If the length of the longest side of a right triangle is 3 more than the length of the shorter side the length of the hypotenuse is 3 more than the length of the longer side find length of each side?

9,3,6 The dimensions given above would not be suitable for a right angled triangle which presumably the question is asking about. The dimensions suitable for a right angled triangle in the question are: 9, 12, 15.


What could not be the lengths of the sides of a right triangle 9ft 12ft 15ft or 4cm 7.5cm 8.5cm or 5in 10in 15in or 1.5m 2m 2.5m?

5" by 10" by 15" cannot be a right angled triangle because the square of the hypotenuse (longest side) must be equal to the sum of the squares of the other two sides.Proof:152 = 22552 + 102 = 25 + 100 = 125225 is not equal to 125 so the triangle is not a right angled triangle.All the others are right-angled triangles:92 + 122 = 152 [81 + 144 = 225]42 + 7.52 = 8.52 [16 + 56.25 = 72.25]1.52 + 22 = 2.52 [2.25 + 4 = 6.25]Answer9ft, 12ft, 15ft9² + 12² = 81 + 144= 225= 15²Which agrees with Pythagoras' Theorem, so this is a right-angled triangle.4cm, 7.5cm, 8.5cm4² + 7.5² = 16 + 56.25= 72.25= 8.5²Which agrees with Pythagoras' Theorem, so this is a right-angled triangle.5in, 10in, 15inThis one doesn't obey the triangle inequality, so it isn't a triangle at all. Anything that isn't a triangle isn't a right-angled triangle, and therefore we don't need to check it against Pythagoras' Theorem. But just to be thorough:5² + 10² = 25 + 100= 12515² = 225≠ 125Which disagrees with Pythagoras' Theorem, so this is not a right-angled triangle.1.5m, 2m, 2.5m1.5² + 2² = 2.25 + 4= 6.25= 2.5²Which agrees with Pythagoras' Theorem, so this is a right-angled triangle.