Yes you must charge it before hooking it up. You can charge it with a 12 volt light bulb with leads or a voltmeter.
In order to feel 9V on your tongue, you need enough current, for enough time, for your brain to recognize the current.Homemade capacitors tend to be rather low in capacitance. The resistance of your tongue might then discharge the capacitor rather quickly, and you might not notice the voltage before it goes to zero. Try this with a large capacitor, such as a few hundred microfarads and see what happens. Please do not charge the capacitor to more than 9V - you do not want to hurt yourself!
because without using capacitor or resistor in a circuit,it cant be complete.Resistor is used to protect the circuit by giving a certain amount of voltage.Capacitor is used to charge and discharge purpose.
The time it takes to fully charge a capacitor depends on the capacitance and resistance of the circuit; the voltage is irrelevant. The equation you need is:t = 5RCwhere: t = time in seconds, R= resistance in ohms, and C =capacitance in farads.So you should now be able to calculate the time for yourself, but remember to convert the resistance into ohms and the capacitance into farads before you insert the figures into the equation.
Both a capacitor and battery "store charge". However, in a battery there is a chemical reaction that continues to generate charge. You apply a charge across the "plates" of a capacitor and it will decay over time from leakage or through a discharge resistance to ground in the circuit. You need really large capacitors to store meaningful amounts of charge, to take the place of a battery for example.
because resistance is restricting the current and voltage, so for it be accurate you need to know what the voltage and the amps are.AnswerCapacitance is quite independent of resistance and, therefore, it will NOT vary if resistance is changed.
In order to double the voltage across a capacitor, you need to stuff twice as much charge into it.
well...a capacitor RELEASES charge which if BUILT up. that's why... lets say that you have a bucket...and you want to flood a small area...you need to fill up ( charge) the bucket before you can flood (discharge) ANSWER: It has the possibility to discharge if a path can be found. ITS property is to store potential
In order to feel 9V on your tongue, you need enough current, for enough time, for your brain to recognize the current.Homemade capacitors tend to be rather low in capacitance. The resistance of your tongue might then discharge the capacitor rather quickly, and you might not notice the voltage before it goes to zero. Try this with a large capacitor, such as a few hundred microfarads and see what happens. Please do not charge the capacitor to more than 9V - you do not want to hurt yourself!
You need a tube, a coil of wire, a magnet and a capacitor to store the charge.
I need answer of this question plz as soon as possible
Capacitors act like tiny storage batteries made of two plates separated by a thin insulator or air. When one plate is charged negative and the other positive, they build up a charge that remains when the current is removed. When its power is required, the circuit is switched to conduct current between the two plates, and the capacitor releases its charge.AnswerCapacitors don't really store charge at all. They allow negative charge to be transferred from one plate to the other, thus establishing an electric field between their plates. But there is no net increase in charge -the amount of charge on the capacitor's plates, after 'charging', is exactly the same as there was before 'charging' -it's just moved around! What capacitors 'store' is energy, not charge.
because without using capacitor or resistor in a circuit,it cant be complete.Resistor is used to protect the circuit by giving a certain amount of voltage.Capacitor is used to charge and discharge purpose.
The time it takes to fully charge a capacitor depends on the capacitance and resistance of the circuit; the voltage is irrelevant. The equation you need is:t = 5RCwhere: t = time in seconds, R= resistance in ohms, and C =capacitance in farads.So you should now be able to calculate the time for yourself, but remember to convert the resistance into ohms and the capacitance into farads before you insert the figures into the equation.
They have capacitors which hold a charge. So, if you are attempting to work on one, you need to be careful, because you could accidentally discharge the capacitor and electrocute yourself.
You need to charge, you need sufficient energy and food before you run.
It depends on the amount of current available to charge or discharge. On the surface, I would say that you can discharge a capacitor faster than you can charge it, because the charge rate is limited by the current available in the power supply, while the discharge current could be quite high, because you could just apply a short circuit conductor around the capacitor. Of course, this could damage the capacitor. In truth, the equation of a capacitor is...dv/dt = i/C, which means that, given the same charge or discharge current, the rate of change of voltage would be the same.AnswerThe time taken to fully charge, or to fully discharge, a capacitor is given by the equation: time = 5 CR, where C represents its capacitance, in farads, and R represents the resistance of the circuit supplying the capacitor, in ohms. By 'fully charge', we mean bring the potential-difference across the capacitor's plates to the same value as the applied potential difference.If the external voltage source is replaced with a short circuit then, providing the resistance of the circuit hasn't changed, the discharge time will be exactly the same as the charging time. If the resistance is changed, then the same equation applies, but you need to insert the new value of resistance.
In general, no. You need to use the correct capacitor as designed for the circuit.