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Answered 2012-12-07 13:17:01

The model 1890 Winchester was only chambered in .22 short,22long,22 long rifle,or 22WRF calibers which were all rimfire calibers.

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The chambering will be stamped right into the barrel.Since it's a 94, it will probably be stamped 30 WCF (Winchester Center Fire) which today is called 30-30 Winchester

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The gun is chambered for the 32 caliber Winchester center fire cartridge. Also known as the 32-20.

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WCF = Winchester Center Fire

Winchester Center Fire.

Your rifle is a Model 94, named for the year of introduction, 1894. 30 WCF is the correct name of the ammunition it fires, .30 caliber Winchester Center Fire, the original name for the .30-30 cartridge.

The letters WCF stand for Winchester Center Fire.

If you are referring to the 32 W.C.F. or 32 W.S. (Winchester Special), both are center fire. Bert H.

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Yes.The Winchester model 1876 rifle was the only rifle made by Winchester that was chambered for the 45-60WCF(winchester center fire).

WCF stands for Winchester Center Fire.

The simple answer is fouling in the barrel from the powder. Any BP gun needs to have the barrel "seasoned" much like a cast iron pan. Cleaning after each shot is the best way to prevent the seating problem. Run a patch down the barrel saturated with a non petroleum cleaner like Thompson center #17, follow it with 2 dry patches to remove the fouling. That should cure the loading trouble. As time and more shots go by it will get easier and need less effort to clean.

The Thompson Center hawken that I have,has a barrel that is 28 inches long.

We know that an octagon is an eight-side polygon. Since each side has the same distance form the center of the circumscribed circle of the octagon, this octagon is a regular octagon. If we draw the radii of the circle (their endpoints there are at the vertexes of the octagon), we form 8 isosceles triangle, which radius represents two their congruent sides with a measure of 7.5 cm, and the distance drawn from the center of the circle to the sides of the octagon represents their altitudes with a measure of 6.9 cm. So, by using the Pythagorean theorem we can find the half of the side of the octagon, which is: 7.5)^2 - (6.9)^2 = 8.64 Since one half of the octagon side is square root of 8.64, the whole side is 2(square root of 8.64) Thus the perimeter of this octagon is approximately 47 cm [8 x 2(square root of 8.64)].