It would seem that the pain would be less. You really need to ask you doctor this question.
S-1 is the shorthand form for writing Sacral vertebrae #1. So a child with S-1 spina bifida just means that their spina bifida lesion is located at sacral vertebrae #1. This vertebrae is located in the lower back, just above the hips.
Spina Bifida occurs on the spinal cord .The spinal cord is divided into different areas for labelling .The bottom is the sacral area, which is divided in sections S5-S1, then the next area is Lumbar L5-L1, the next section is Thoracic T-12-T1 and finally the last section cervical C8- C1. I would assume if it said L1 that it means Lumbar section 1 where the lesion or mark is on the back.
strlen(s1) to find the length of the string s1 strcpy(s1,s2) copy source string to destination string(i.e copies s2 to s1,s2 remain unchanged) strcmp(s1,s2) compares s1 and s2 and prints 0 if s1 and s2 are equal,-1 if s2 is greater, 1 if s1 is greater strcat(s1,s2) combines string s1 and s2 to a single word and stores it in s1 strupr() converts lower case string to upper case strlwr() converts upper case string to lower case
yes
Statement S2 is anti-dependent on statement S1 if S2 follows S1 in program order and if the output of S2 overlaps the input of S1. The anti-dependence S1 to S2 define as cross arrow such as S1 |-> S2.
S1
s1 : Continiuos running
what is the treatment for a desiccated L5-S1
When there is narrowing in the space between the spinal discs, it can be a result of a herniated or bulging disc or stenosis. Disc space narrowing from L3-S1 can cause severe pain in the lower back and legs.
Definition: A set S1 is a superset of another set S2 if every element in S2 is in S1. S1 may have elements which are not in S2.
/* ellipses, ..., used to emulate indentation */ int strcmp (const char* s1, const char* s2) { ... while (s1 != NULL && s2 != NULL) { /* scan both strings */ ... ... if (*s1 < *s2) return -1; /* first string less */ ... ... if (*s1 > *s2) return 1; /* first string greater */ ... ... s1++; ... ... s2++; ... } ... if (s1 == s2) return 0; /* strings equal or both empty */ ... if (s1 != NULL) return 1 else return -1; /* first string longer(1) / shorter(-1) */ } A slightly less computation-intensive version is: int strcmp(const char* s1, const char* s2) { ... if (s1==s2) ... ... return 0; ... while (*s1) ... ... if (*s1++^*s2++) ... ... ... if (--s1<--s2) ... ... ... ... return -1; ... ... ... else ... ... ... ... return 1; ... return 0; }