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The oxidation state of 'Mn' in KMnO4 is +7 after reaction as oxidizing agent 'Mn; becomes +2 so change in oxidation number is '5' the formula mass divided by change in oxidation number is equal to equivalent mass or weight, 158/5 = 31.7

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14y ago
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13y ago

KMnO4 has a Molar mass of 158.04 g/mol

There are two possibilities:

1. KMnO4 as an oxidizer in acidic media:

MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant)

I.e. 5 Equivalents per mole, so equivalent mass of KMnO4 = M/5 = 158.04/5 = 31.61 gram/equivalent

2. KMnO4 as an oxidizer in neutral or basic media:

MnO4- + 2H2O + 3e- --> MnO2(s) + 4OH- (gained 3 electrons)

In this case: 3 equivalents per mole, so equivalent mass of KMnO4 = M/3 = 158.04/3 = 52.68 gram/equivalent

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12y ago

the equivalent weight of kmno4 when converted to mno2 is 158/3

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11y ago

mol wt/5

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Q: What is the Equivalent weight of KMnO4 in different medium?
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What is the ratio of equivalent weight of kmno4 in acidic and basic and neutral medium?

determine the eqoivalent weight of KMno4 in basic medium


What is the equivalent weight of potassium chromate What is the equivalent weight of KMnO4 in neutral medium?

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In manufacture of potassium permanganate by electrolysis of k2mno4 what should be the equivalent weight of kmno4 how much kmno4 will be produced by 96478 coulombs or one farady?

Equivalent weight of KMnO4 is equal with molar weight of KMnO4. The some is and for K2MnO4, K2MnO4 - e +OH- --------- KMnO4 + KOH In general, Equivalent weight = Molar weight / Number of electrons that take or give one molecule Equivalent weight of KMnO4 = Molar weight of KMnO4 / 1


Why acid is added in KMnO4 titration?

as kmno4 acts as a strong reducing agent only in acid medium


How do you prepare the 1N concentration of potassium permamganate solution?

N (normality) describes a solution that contains 1 gram equivalent weight (gEW) per liter solution. An equivalent weight is equal to the molecular weight divided by the valence (here it gets a little tricky, for acids ands bases it refers to the number of H+ or OH-, in salts it must be expressed which ion is meant unless the ratio is 1:1). In the case of KMnO4, equivalent wt is reaction specific. When KMnO4 is used in acid medium as oxidiser, 5 electrons are gained by Mn atom. So equivalent wt of KMnO4 in acid medium = Molecular wt/no.of electrons gained in redox reaction = 158/5 =31.6. So for 0.1N KMnO4 solution, you have to dissolve 3.16g KMnO4 in 1L water. (Usually a little bit excess is taken, say 3.25g, since some crystals of KMnO4 will be remained undissolved that have to be removed by filtration. So eventhough u r preparing 0.1N KMnO4 solution by accurate weighing,it is not a primary standard and u have to standardise it against a primary std such as oxalic acid or sodium oxalate. In alkaline or neutral medium, reaction of KMnO4 is different and Mn gains 3 electrons in redox reaction. So, for alkaline medium redox titrations, equivalent wt of KMnO4 will be 158/3 = 52.6. So for 0.1N KMnO4 solution in alkaline medium redox titration, dissolve 5.26g in 1L water.


What is the equivalent weight of Bayer's reagent?

Alkaline soln.of KMnO4 functions as a Bayer reagent in which it turns into MnO4. Hence change in the oxidation state = 7-4=3.Sometimes equivalent weight = Original weight / Change in the oxidation state=158/3 = 52.6Hope it helps..


How do you prepare standard solution of potassium dichromate to compare icteric index of serum?

for preparing 0.1 normal solution of potassium permanganate you have to disssolve 3.16 g potssium permangnate in 1L water bt in alkaline or neutral medium reactions of potassium permanganate is different and Mn gains 3 electrons in redox reaction,so far alkaline medium redox titration equivalent wt of KMnO4 will be 158\3=52.6.so far,0.1 N KMnO4 in alkaline medium redox titration dissolve 5.26 g in 1L sol.


Chemical symbol for permanganate?

The formula for potassium permanganate is KMnO4


What is the amount percentage of manganese in potassium permanganate KMnO4?

% by mole. There are six elements in KMnO4 only one is K so 1/6 which is 16.67% % by mass. Molar weight of K 39grams/mole. Molar weight of KMNO4 154 grams/mole so 39/154 =25%


Why in titration of kmno4 no indicator is used?

Because KMnO4 is an internal indicator.. No need to have any indicator.. it has distinctly different colour when it is reduced


How many ml of 0.24M of Na2so4 will be oxidised by 180 ml of 0.32 kmno4 in acid medium?

23453 ha ha


What are kmno4?

acidicness number of kmno4