when an animal cell is placed in a concentrated or diloute solution, it soakes up the water but because animal cell do not have cell walls like plant cells they will eventually burst.
It would grow bigger and burst
What can happen to animal cells when placed in a hypotonic solution explain
It would be shrunken .
The cell will dehydrate.
Hypertonic solution: highly concentrated, therefore water exits the cell, attracted to the solution. Cell ends up deflated-looking.Hypotonic solution: not very concentrated, therefore water enters cell, attracted to the solution inside the cell. Cell ends up looking like it's going to burst (and actually can burst).
It will burst from the pressure caused from the imbalance of osmosis.
It will die.
This is because of the process of osmosis. When an animal cell is placed in concentrated salt solution (of lower water potential than the animal cell/ hypertonic relative to the cell), water molecules will leave the cell and move into the salt solution to achieve equilibrium of water potential. This causes the animal cell to decrease in size and shrink. Spikes appear around the cell, and the cell is said to be crenated.
It would shrink.
When an animal cell is placed into a hypertonic solution, the water will generally flow out of the cell in an effort to balance the concentration of solutes.
If excess water moves into an animal cell, it will eventually burst. This happens if the cell is placed in a hypotonic solution (a solution with a lower solute concentration than the cell).
If an animal cell is placed in a hypotonic solution, there will be a net movement of water into the cell and it will eventually burst. If an animal cell is placed in a hypertonic solution, there will be a net movement of water out of the cell and it will shrink.
In a hypertonic solution the cell's fluid will move out of the cell and into the surrounding solution (osmosis) , causing the cell to shrink.
The cells burst because the solution is diluted i.e.,the cell is more concentrated than the solution. So the cells gain water by osmosis and since animal cells have no cell wall they will fill with water until they become so stretched that they burst.
A hypertonic solution is less concentrated compared to the cytoplasm of the animal cell. When an animal cell is placed in a hypertonic solution, water diffuses across the selectively permeable cell membrane in an attempt to form an equilibrium between the two liquids. If the solution is hypertonic enough compared to the cell's cytoplasm, the cell would swell and could possibly explode.
It can possibly burst.
Euthanasia solution - which is basically an overdose of anaesthetic, but it is that concentrated that the animal goes into a deep sleep and its heart stops.
An animal cell in a hypertonic solution will shrivel up because the water inside the cell will diffuse to the outside where there is less water and more ions.
A hypotonic solution contains less solutes than the cell. This means there will be a net movement of water into the cell. An animal cell will eventually burst in this situation.
osmosis will take place and finally cell will burst.
The cell shrinks or in simple exo-osmosis occur...
the cell will become flaccid or will undergo plasmolysis because the concentration of solute is more inside the cell and less in the solution.
If you put a animal cell in hypertonic than the animal cell will shrink because hypertonic contains salt which the cell is not use to so it will shrink.
CAFO (concentrated animal feeding operation)
The water flows through the cell and stays the same size... nothing happens:P