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There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.

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0There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.

They are: -39 -41 -43 = -123

find the two consecutive odd integers with a sum of 152

123/3 = 41 so integers are 39, 41 and 43

The sum of two consecutive odd integers is an even number. There is no possible answer to this question.

The four consecutive odd integers are 43 + 45 + 47 + 49 = 184

The numbers are 39, 41 and 43.

123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.

The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.

The integers are 11, 13 and 15.

The integers are 13 and 15.

The integers are 5 and 7.

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

The sum of any two consecutive integers must be an odd number. So this question is incorrect.

They are consecutive odd integers: 25 and 27.

Those three odd integers are 43, 45, and 47.

Are not all integers spaced out to be odd then even then odd then even etc (eg 1,2,3,4,5,6,7,8,9,10, etc) and therefore there is no such thing as two consecutive odd integers.

For three consecutive odd integers to have the sum 123, the equation N + N+2 + N+4 = 123 must be solvable with N being an odd integer.N + N+2 + N+4 = 1233N + 6 = 1233N = 117N = 39Since 39 is an odd integer, the solution is 39, 41, and 43.If N were even, or if N resolved to a non-integer, then the problem would have been incorrectly stated and unsolvable.

There are two consecutive odd integers whose sum is 176. They are 87 and 89.

There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.

For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.

Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.

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