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The centre is (3,-1) and the radius is sqrt(10).

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0Centre = (0,0), the origin; radius = 11

That's the equation of a circle with its center at the origin and a radius of 8.

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2

It is the equation of a circle with radius of 6 and its center at the origin.

Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2

depends on the equation.

Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.

x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5

The equation of any circle, centered at the origin, is x2 + y2 = r2, where r is the radius.

If that equals 16 then the radius is 4

The radius is sqrt(12) = 3.464 (rounded)

The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.

A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6

Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4

The equation of the circle is: x^2 + y^2 = 81

The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1

The ' 1 ' in that equation is the radius.

5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.

The answer is indeterminate. For example, if the equation is of the form x2 - 2ax + y2 - 2by = 25, all that can be said of the radius of the circle is that it is greater than 5.

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.

x2 + y2 = r2, where r is the radius.

(x-9)2 + y2 = 484The center is atx = 9y = 0The radius of the circle is 22 .

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