Let,
Coefficient of viscosity of liquid = eta
Radius of sphere = a
velocity of sperical body = v
Dimensionally it can be proved that
F = k eta*a*v
Experimentally Stoke found that
k = 6*pi
therefore, F = 6*pi*eta*a*v
This is Stoke's law.
the tangential velocity is equal to the angular velocity multiplied by the radius the tangential velocity is equal to the angular velocity multiplied by the radius
Use the formula for centripetal acceleration: velocity squared / radius.
velocity: v = 121 m/s radius: r = 4230m circumference: C = 2 * (pi) * radius = ~26578m time: t = s/v = distance travelled / velocity = circumference / velocity = 220 s
Density = mass/ volume volume= 4/3(pie)(r^3) ***r= radius in meters** so find volume then divide mass by volume and there you go.
Use the formula a = v2 / r, with v = velocity (speed, actually) in meters/second, r = radius in meters. The answer will be in meters per square second.
Cyclotron pulse multiplied with the maximum radius
Assuming equal velocity. The alpha particle has twice the charge but four times the mass so it would have the wider radius.
Increase in radius affect the increase of the centripetal force on a particle in uniform circular motion. An increase in radius would cause a decrease in the force if velocity remains constant.
10T because F=mV^2/radius in a circle. So if the velocity and radius are the same then you will just multiply the mass by ten (10mV^2/radius) giving you 10 times your period
I believe the relationship between the radius and velocity is: V = (127 2⁄15 x f x R)½ Where V = velocity, f = lateral load factor, R = Radius I believe the relationship between the radius and velocity is: V = (127 2⁄15 x f x R)½ Where V = velocity, f = lateral load factor, R = Radius
Assuming that angles are measured in radians, and angular velocity in radians per second (this simplifies formulae): Radius of rotation is unrelated to angular velocity. Linear velocity = angular velocity x radius Centripetal acceleration = velocity squared / radius Centripetal acceleration = (angular velocity) squared x radius Centripetal force = mass x acceleration = mass x (angular velocity) squared x radius
Angular velocity just means how fast it's rotating. If youaa want more angular velocity, just rotate it faster or decrease the radius (move it closer to the center of rotation). Just like force = rate of change of momentum, you have torque= rate of change of angular moment Or We can increase the angular velocity of a rotating particle by applying a tangential force(i.e. accelaration) on the particle. Since the velocity of the particle is tangential with the circle along which it is moving, the tangential accelaration will not change the diriction of the velocity(as angle is 0),but will cause a change in magnitude. Thus angular velocity will increase.
the velocity will be velocity divided by square root of 2
linear velocity= radius* angular velocity
the tangential velocity is equal to the angular velocity multiplied by the radius the tangential velocity is equal to the angular velocity multiplied by the radius
mass, velocity and radius
For two bodies with equal radius, the more massive has the greater escape velocity. For two bodies with equal mass, the one with smaller radius has the greater escape velocity. Both conditions listed in the question indicate greaterescape velocity.