the complete chemical equation for KI AgNO3 and HNO3.the reaction between KI and Ag NO3 can take place you asked a wrong question.AgNO3 + KI = AgI + KNO3
Reaction type: double replacement
Complete Ionic equation:
Ag+(aq) + NO3-(aq) + K+(aq) + I-(aq) = AgI(s) + NO3-(aq) + K+(aq)
KCl + AgNO3 = KNO3 +AgCl
KI+ AgNO3+NH3
K(NO3)2 + AgCl + H2
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
The balanced equation is as follows: KIO3 + AgNO3 --> KNO3 + AgIO3
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
The one that is ionic is KI, potassium iodide.
AgNO3 + KI ----> AgI(ppts.) + KNO3
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
The balanced equation is as follows: KIO3 + AgNO3 --> KNO3 + AgIO3
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Do you want that for Monopotassium phosphate, dipotassium phosphate, or tripotassium phosphate? --------------------------------- To clarify for the previous answerer, ionic compounds inherently don't use the mono-, di-, or tri- system used for molecular compounds. Instead, when a cation and an anion is supplied, the ionic compound assumes the number of cations and anions that will generate a neutral ionic compound. In this case, since K is 1+ and PO4 is 3-, the compound potassium phosphate always refers to K3PO4. Therefore: 3AgNO3 + K3PO4 -> 3KNO3 + Ag3PO4
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
The one that is ionic is KI, potassium iodide.
No- KI, Potassium iodide is an ionic compound.
AgNO3 + KI ----> AgI(ppts.) + KNO3
There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2. The "slow step" is H2O2 + I- --> OI- + H2O The "fast step" is H2O2 + OI- --> H2O + I- O2 The overall is: 2 H2O2 --> 2H2O + O2
KI(aq) + AgNO3(aq) --> AgI(s) + KNO3(aq) is a double replacement reaction.
neutral because its an ionic compound.
Yes, AgI is insoluble, therefore will form a precipitate.