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Formula for molality

Updated: 8/9/2023
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15y ago

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== Molality== (1000xMolarity)/((1000xdensity of solution)- (MolarityxMolecular weight of Solute)) ==

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15y ago
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15y ago

molality (m) = (No. of moles of solute) / (weight of solvent in kilograms)

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12y ago

Molarity is defined as grams of solute dissolved in 1 liter of solution and

molality is defined as grams of solute dissolvd in 1Kg of solvent

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9y ago

Molality is the number of moles of solute dissolved in one kilogram of a solvent. It is found by dividing the number of moles of solute by the weight of solvent measured in kilograms.

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10y ago

molality= moles solute/kg solvent

b= n / m

b - molality

n - moles solute

m - kg solvent, not: kg solution!

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10y ago

The molality is the ratio between the mass of a solute (expressed in moles0 and the mass of the solvent (expressed in kilograms). The term is now anachronic.

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What quantity represents the ration of the number of moles of solute per kilogram of solvent?

Mol is a cocentration unit !


What is the molality of a substance made by dissolving 2 moles of NaOH in 10 kg of water?

Molality is moles solute per kilograms of solvent, so 2/10=0.2m.


What are the molality and mole fraction of solute in a 25.5 percent by mass aqueous solution of formic acid (HCOOH)?

The molality is 5,54.


What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?

Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m


What would you needto do to calculate the molality to 10 molecules of NaCl in 200 molecules of water?

Molality of a solution is defined as the number of gram moles, for molecular compounds, or gram formula unit masses, for ionic compounds, mixed with each kilogram of solvent. Sodium chloride is the solute in the question, and water is the solvent. Avogadro's Number is defined as the number of formula units required to constitute one gram formula unit and has the value of about 6.022 X 1023. Therefore, 10 formula units of NaCl constitutes 10/(6.022 X 1023) or about 1.6606 X 10-23 gram formula unit. The gram molecular mass of water is 18.0518. Therefore, 200 molecules of water contains (200)(18.0518)/(6.022 X 1023) or about 599.5 X 10-23 grams or 0.5995 X 10-23) kilograms. Therefore, the molality of the given mixture is 1.6606/0.59995* or about 2.768. ________ *The number 10-23 appears in both numerator and denominator, and therefore need not be included in this fraction.