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Full load copper loss of a 100 KVA transformer is 800W Its copper loss at 75 percent load will be?
Wiki User
∙ 11y ago
100 is to 800 as 75 is to X. Cross multiply, 100 x X and 800 x 75, 100X = 60000. To get rid of the 100 divide it into both sides of the equation. X = 600.
If the copper loss is linear, at 75 percent the copper loss will be 600 watts.
Wiki User
∙ 11y ago
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What is the reason to use open circuit and short circuit methods to find Transformer losses?
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
Can a Auto transformer have more load losses than its no load losses?
Power transformers have both no load and full load losses. The key is copper wiring, as copper varies with the square inches of the secondary and primary currents.
How to calculate transformer core loss and iron loss?
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
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What losses can be measured in a short circuit test of a transformer?
Winding copper losses of a transformer can be measured in a short circuit test of a transformer. Impedance voltage is given to the primary and the secondary is often shortcircuited. (some times the reverse is done of this). Full load currents are made to flow in both primary and secondary circuits. This current flow heats up the 2 windings of the transformer. Power consumed at this time gives the transformer copper losses.
What is the reason to use open circuit and short circuit methods to find Transformer losses?
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
Is this statement true or false the maximuim efficiency of transformer is occured when iron losses is equal to full load copper losses?
Copper losses are directly related to loading of the transformer. Iron (core) losses are a result of magnetizing of the core of the transformer, and are relatively constant from no load to full load. With this in mind, it should be clear that the above statement is false. Maximum efficiency results with low core losses, and low copper losses. Copper losses cannot be helped, so it is important to minimize core losses to increase the efficiency of a transformer.AnswerYes, it is perfectly correct -well, with the proviso that transformers normally operate somewhat below full load and, so, are designed to achieve maximum efficiency somewhat below full load. A transformer's maximum efficiency does indeed occur when the copper losses and iron losses are equal. Unfortunately, the mathematical proof of this is too complicated to reproduce here, I suggest that you check out any reputable electrical engineering textbook.
Can a Auto transformer have more load losses than its no load losses?
Power transformers have both no load and full load losses. The key is copper wiring, as copper varies with the square inches of the secondary and primary currents.
What is the full form of CT PT transformer?
CT=========current transformer PT=========potential transformer these are the instrumental transformers.
How to calculate transformer core loss and iron loss?
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
Where to download transformer the game full version?
güzel
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the internet..... ._.
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