He formula for potassium dichromate is KËÃCrËÃOËÈ How many grams of oxygen will be in 2 moles of potassium dichromate?
The formula for potassium dichromate is KËÃCrËÃOËÈ. How many grams of oxygen will be in 2 moles of potassium dichromate?
The formula for potassium dichromate is K2Cr2O7 How many grams of oxygen will be in 2 moles of potassium dichromate?
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
This is more of a math question that requires a bit of knowledge of chemistry. So it helps to know the steps of this answer mathematically. Additionally it's worth noting that there are a number of ways to answer this question. The method I provide may take an extra step, but it allows for a better understanding of the process. First we need to know some basic information about potassium permanganate, KMnO4. This basic information…
The formula shows that each mole or formula unit contains one gram atomic mass of each of potassium and manganese and four gram atomic masses of oxygen. the gram atomic mass of potassium is 39.0983, that of manganese is 54.9380, and that of oxygen is 15.9994. Therefore, the required answer is: 2.47[39.0983 + 54.9380 + 4(15.9994)] or about 390 grams, to the justified number of significant digits.
A sample of a substance contains 39.8 g of potassium and 8.2 g of oxygen What is the percentage composition of each in the sample?
What is the empirical formula of a compound that is 40 percent sulfur and 60 percent oxygen by weight?
We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula
The formula of potassium sulfate is K2SO4, and the gram formula unit mass is 174.25. The formula shows that each formula unit contains 7 total atoms, and a full gram formula unit always contains Avogadro's Number of formula units. Therefore, the answer is 7(43.5/174.25)(6.022 X 1023) or about 1.50 X 1024 atoms, to the justified number of significant digits.
To find empirical formulas, masses of elemental reactants must be changed to gram atoms by dividing the mass by the gram atomic masses of each element. Thus, 16 grams of sulfur constitutes 16/32.06 or 0.50 mole to the justified number of significant digits, and 24 grams of oxygen constitutes 24/15.9994 or 1.50 moles of oxygen to the justified number of significant digits. Therefore, the atomic ratio of oxygen to sulfur in the compound is 1.50/0.50…