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Help with stoichiometry show steps How many grams of KClO3 must be decomposed to yield 30 grams of oxygen?
Wiki User
∙ 14y ago
2 KClO3 -> KCL + 3O2
Molar weight of O2 = 32 grams/mole (so close it doesn't matter)
30 grams/32grams/mole = 0.9375 moles
Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?)
now if we have 3 moles of O2 then we have 2 moles of KCl.
If we have one mole of O2 then we have 2/3 moles of KCL
What ever moles we have of O2 we must multiply it by 2/3 to get the moles of KCl
So we have 0.9375moles of O2 x 2/3 = 0.625 moles of KCl
So 0.625 moles of KCl x 74.5 grams/mole KCl = 46.5625 grams KCl
Wiki User
∙ 14y ago
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How many moles of KClO3 on decomposition give 1 mole of oxygen?
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
What is the grams of substance in 2 moles of KClO3?
Alls you do to find a molar mass is add up all of the atomic masses. Potassium=39.09 Chlorine= 35.453 Oxygen(3)=15.999. So KClO3 would equal 271.65g to a mol? Then I think to find the number of atoms of each you would take the atomic mass * avacodo's number so it would be for example chlorine. 1gCl(35.453/1)(6.022*10^23/1) However I might be wrong on that part.
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
When 46.0 g KClO3 is heated 12.1 g O2 is formed how many grams of KCl is also formed?
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
How many milliliters of O2 will form a STP from 55.2 grams of KCLO3?
I assume you mean the decomposition reaction used to produce O2 in lab. 2KCLO3 -> 2KCl + 3O2 find moles O2 55.2 grams KClO3 (1 mole KCLO3/122.55 grams)(3 mole O2/2 mole KClO3) = 0.67564 moles O2 Now, I use the ideal gas law PV = nRT (1 atm)(V) = (0.67564 mol)(0.08206 L*atm/mol*K)(298.15 K) Volume O2 = 16.53 Liters which is 16530 milliliters ( less significant figures )
How many moles of KClO3 on decomposition give 1 mole of oxygen?
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
What is the grams of substance in 2 moles of KClO3?
Alls you do to find a molar mass is add up all of the atomic masses. Potassium=39.09 Chlorine= 35.453 Oxygen(3)=15.999. So KClO3 would equal 271.65g to a mol? Then I think to find the number of atoms of each you would take the atomic mass * avacodo's number so it would be for example chlorine. 1gCl(35.453/1)(6.022*10^23/1) However I might be wrong on that part.
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
Water decomposes to make 4 gram hydrogen gas and 32 g of oxygen gas what mass of water is decomposed?
36 grams
When 46.0 g KClO3 is heated 12.1 g O2 is formed how many grams of KCl is also formed?
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
Why is stoichiometry important to chemistry?
Stoichiometry is important to chemistry because it is how you find important things in chemistry like particles, grams, moles and liters.
How many grams of oxygen are produced when 11.5 grams NO2 is formed?
You can't answer this question unless you know the the NO2 was formed FROM. You need to write the balanced reaction for the reaction and then use stoichiometry to solve for the amount of oxygen produce.See the Related Questions to the left for how to write a balanced reaction and how to use stoichiometry to solve this type of problem.
A molecule of carbon dioxide contains two atoms of oxygen to one atom of carbon. If 440 grams of carbon dioxide is completely decomposed into carbon and oxygen what mass of oxygen would be produced.?
Balanced equation always and first. Decomposition reaction. CO2 -> C + O2 440 grams CO2 (1 mole CO2/44.01 grams)(1 mole O2/1 mole CO2)(32 grams/1 mole O2) = 319.93 grams O2 ( call it 320 grams )
How many milliliters of O2 will form a STP from 55.2 grams of KCLO3?
I assume you mean the decomposition reaction used to produce O2 in lab. 2KCLO3 -> 2KCl + 3O2 find moles O2 55.2 grams KClO3 (1 mole KCLO3/122.55 grams)(3 mole O2/2 mole KClO3) = 0.67564 moles O2 Now, I use the ideal gas law PV = nRT (1 atm)(V) = (0.67564 mol)(0.08206 L*atm/mol*K)(298.15 K) Volume O2 = 16.53 Liters which is 16530 milliliters ( less significant figures )
How many grams of calcium oxide will remain after 12.25grams of calcium carbonate is completely decomposed?
6,863 grams of CaO
Stoichiometry grams of N2 are needed to produce 20 grams NH3 N2 plus H2 NH3?
16,45 g nitrogen are needed.
If 6.500 grams of hydrogen sulfide is decomposed to get 0.384 grams hydrogen how much sulfur is there?
The mass of sulfur is 6,118 g.
