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How do I make a %CO2 solution with Na2CO3 based on its stoichiometric relation and solubility?

Hi, I have a doubt about making an equivalent %co2 solution with sodium carbonate. I have attached the reference equation quoted in the research article. If anyone knows how to derive the equation kindly help me. How do they arrive at 1.3g/L for 5% Co2 and help me to find out for 50% co2 ***reference*** pH=6.30+log [ HCO3− ] −log [ CO2] pH=10.09+log [ CO3 2- ] −log [ HCO3-] The values of sodium carbonate concentrations corresponding to 5%, 10%, 15%, 20% and 30% CO2 concentrations at pH 7 are 1.3 g/L, 2.6 g/L, 3.8 g/L, 5.1 g/L, and 7.6 g/L, respectively. ****reference***

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divyasri

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2022-12-06 06:10:07

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Q: How do I make a %CO2 solution with Na2CO3 based on its stoichiometric relation and solubility?
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Standardization of hcl solution with primary standard na2co3 solution?

solution containig (3.3)gm na2co3 .h2o in (15ml)


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It is a basic (alkaline) solution.


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The solubility of sodium carbonate in water at 20 0C is approx. 22 g Na2CO3/100 g water.


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The pH of sodium carbonate solution is about 11.


How many moles of Na2CO3 are there in 10.0 L of 2.0 M soluton?

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What happens when you mixed the magnesium chloride solution with the sodium cabonate solution?

MgCl2 + Na2CO3 = 2NaCl + MgCO3


When 2.61 of solid Na2CO3 is dissolved is sufficient water to make 250 mL of solution the concentration of Na2CO3 is?

You need to mention the unit for 2,61.


How do you prepare 250ml 15m solution of naco3 in a volumetric flask do presume a solvent ie h20 but then you have to presume volumes and conc and because 15M wanted you cant use the flask to dilute?

Did you mean 250 mL of 0.15 M Na2CO3? (It's impossible to make a 15 M Na2CO3 solution, as Na2CO3 is not that soluble.) Yes, you can assume that this will be an aqueous solution. Steps. 1. Calculate the mass of solid Na2CO3 needed. 2. Place this mass of Na2CO3 in the volumetric flask. 3. Add some water and swirl to dissolve the Na2CO3. 4. Carefully add more water until the total volume of solution is 250 mL, as indicated by the line etched on the neck of the volumetric flask. 250 mL x 1 L x 0.15 mol Na2CO3 x 105.99 g Na2CO3 = 4.0 g Na2CO3 needed ........... 1000 mL ......... 1 L ..................1 mol Na2CO3

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