Be notified when an answer is posted
solution containig (3.3)gm na2co3 .h2o in (15ml)
It is a basic (alkaline) solution.
The solubility of sodium carbonate in water at 20 0C is approx. 22 g Na2CO3/100 g water.
The pH of sodium carbonate solution is about 11.
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
na2co3 is primary standard,because,molarity remains same with time,and it is of high molecular weight
Sodium carbonate is dissociated in water.
==>Na2CO3 + CuSO4 Na2SO4 + CuCO3
The chemical formula of sodium carbonate is Na2CO3. A solution hasn't a formula.
MgCl2 + Na2CO3 = 2NaCl + MgCO3
You need to mention the unit for 2,61.
Did you mean 250 mL of 0.15 M Na2CO3? (It's impossible to make a 15 M Na2CO3 solution, as Na2CO3 is not that soluble.) Yes, you can assume that this will be an aqueous solution. Steps. 1. Calculate the mass of solid Na2CO3 needed. 2. Place this mass of Na2CO3 in the volumetric flask. 3. Add some water and swirl to dissolve the Na2CO3. 4. Carefully add more water until the total volume of solution is 250 mL, as indicated by the line etched on the neck of the volumetric flask. 250 mL x 1 L x 0.15 mol Na2CO3 x 105.99 g Na2CO3 = 4.0 g Na2CO3 needed ........... 1000 mL ......... 1 L ..................1 mol Na2CO3